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dedylja [7]
2 years ago
5

A series RLC circuit contains an inductor with a value of 200 millihenries and a capacitor with a value of 0.1 microfarad. What

is the resonant frequency of this circuit
Mathematics
1 answer:
vaieri [72.5K]2 years ago
3 0

Answer:

  1125.4 Hz

Step-by-step explanation:

The resonant frequency is the frequency at with the inductive reactance is equal to the capacitive reactance. It is given by the relation ...

  f=\dfrac{1}{2\pi\sqrt{LC}}

where L is in henries, and C is in farads.

__

For the given circuit values, the resonant frequency is ...

  f=\dfrac{1}{2\pi\sqrt{0.2\cdot0.1\times10^{-6}}}\approx1125.4

The resonant frequency of this circuit is about 1125.4 hertz.

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Choose the best coordinate system to find the volume of the portion of the solid sphere rho <_4 that lies between the cones φ
MrRissso [65]

Answer:

So,  the volume is:

\boxed{V=\frac{128\sqrt{2}\pi}{3}}

Step-by-step explanation:

We get the limits of integration:

R=\left\lbrace(\rho, \varphi, \theta):\, 0\leq \rho \leq  4,\, \frac{\pi}{4}\leq \varphi\leq \frac{3\pi}{4},\, 0\leq \theta \leq 2\pi\right\rbrace

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V=\int_0^{2\pi}\int_{\frac{\pi}{4}}^{\frac{3\pi}{4}}\int_0^4  \rho^2 \sin \varphi \, d\rho\, d\varphi\, d\theta\\\\V=\int_0^{2\pi}\int_{\frac{\pi}{4}}^{\frac{3\pi}{4}} \sin \varphi \left[\frac{\rho^3}{3}\right]_0^4\, d\varphi\, d\theta\\\\V=\int_0^{2\pi}\int_{\frac{\pi}{4}}^{\frac{3\pi}{4}} \sin \varphi \cdot \frac{64}{3} \, d\varphi\, d\theta\\\\V=\frac{64}{3} \int_0^{2\pi} [-\cos \varphi]_{\frac{\pi}{4}}^{\frac{3\pi}{4}}  \, d\theta\\\\V=\frac{64}{3} \int_0^{2\pi} \sqrt{2} \, d\theta\\\\

we get:

V=\frac{64}{3} \int_0^{2\pi} \sqrt{2} \, d\theta\\\\V=\frac{64\sqrt{2}}{3}\cdot[\theta]_0^{2\pi}\\\\V=\frac{128\sqrt{2}\pi}{3}

So,  the volume is:

\boxed{V=\frac{128\sqrt{2}\pi}{3}}

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Step-by-step explanation:

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