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zvonat [6]
3 years ago
13

A group of cyclists went bike riding during a 7-day vacation. They biked 131 miles in the first three days. By the end of their

vacation, they had biked 287 miles in all. How many miles did they bike during each of the last 4 days if they biked the same distance each day?
Mathematics
1 answer:
Nezavi [6.7K]3 years ago
7 0

Answer: 156 miles

Step-by-step explanation:

Given, A group of cyclists went bike riding during a 7-day vacation.

Total distance they biked in first three days = 131 miles

Total distance they biked by the end of the vacation ( i.e. in 7 days ) = 287 miles

Then, the total distance they biked in last four days would be=

(Total distance they biked in 7 days ) - (Total distance they biked in first 3 days )

= 287 - 131 miles

= 156 miles

Hence, they biked 156 miles in last 4 days.

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The amount of chlorine in a swimming pool varies directly with the volume of water. the pool has 2.5 milligrams of chlorine per
djverab [1.8K]

Answer:

Find out the  how much chlorine is in the pool .

To prove

As given

The amount of chlorine in a swimming pool varies directly with the volume of water.

The pool has 2.5 milligrams of chlorine per liter of water.

i.e

2.5 milligrams of chorine = 1 litre of water

There are 8000 gallons of water in the swimming pool.

As 1 gallons = 3.78541 litre (Approx)

Now convert 8000 gallons of water in litres.

8000 gallons = 8000 × 3.78541 litre

                      = 30283.28 litres

Now calculate chlorine in the pool for 30283.28 litres  of waters.

As

2.5 milligrams of chlorine = 1 litre of water

2.5 × 30283.28 milligrams of chlorine = 30283.28 litre of water

75708.2 milligrams of chlorine for 30283.28 litre of water .





3 0
3 years ago
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Kobotan [32]
The correct answer is C. 2,836

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3 0
3 years ago
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Step-by-step explanation:

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Bhurashi did 8 out of 10 math problems and Bishwant did 11 out of 15 similar math problems. Express the number of problems solve
ohaa [14]
8 over 10 times by 100, and 11 over 15 times by 100 to find in percentage. Whichever number is bigger is your answer.
4 0
3 years ago
What is wrong with the following proof that for every integer n, there is an integer k such that n &lt; k &lt; n + 2? Suppose n
expeople1 [14]

Answer:

c)The proof writer mentally assumed the conclusion. He wrote "suppose n is an arbitrary integer", but was really thinking "suppose n is an arbitrary integer, and suppose that for this n, there exists an integer k that satisfies n < k < n+2." Under those assumptions, it follows indeed that k must be n + 1, which justifies the word "therefore": but of course assuming the conclusion destroyed the validity of the proof.

Step-by-step explanation:

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3 years ago
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