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bagirrra123 [75]
3 years ago
5

Help me pls this is hard

Mathematics
2 answers:
Luba_88 [7]3 years ago
6 0

Answer:

I guess it is the Answer C

alisha [4.7K]3 years ago
4 0

Answer:

C

The distance around the edge of the circle

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Assume that a company hires employees on Mondays, Tuesdays, or Wednesdays with equal likelihood.a. If two different employees ar
horsena [70]

Answer:

P(A) = \frac{1}{9}

P(B) = \frac{1}{3}

P(C) = \frac{1}{729}

Step-by-step explanation:

We know that:

Only employees are hired during the first 3 days of the week with equal probability.

2 employees are selected at random.

So:

A. The probability that an employee has been hired on a Monday is:

P(M) = \frac{1}{3}.

If we call P(A) the probability that 2 employees have been hired on a Monday, then:

P(A) =P(M\ and\ M)\\\\P(A)=( \frac{1}{3})(\frac{1}{3})\\\\P(A) = \frac{1}{9}

B. We now look for the probability that two selected employees have been hired on the same day of the week.

The probability that both are hired on a Monday, for example, we know is P(A) = \frac{1}{9}. We also know that the probability of being hired on a Monday is equal to the probability of being hired on a Tuesday or on a Wednesday. But if both were hired on the same day, then it could be a Monday, a Tuesday or a Wednesday.

So

P(B) = \frac{1}{9} + \frac{1}{9} + \frac{1}{9}\\\\P(B) = \frac{1}{3}.

C. If the probability that two people have been hired on a specific day of the week is 3(\frac{1}{3}) ^ 2, then the probability that 7 people have been hired on the same day is:

P(C) = (\frac{1}{3}) ^ 7 + (\frac{1}{3}) ^ 7 + (\frac{1}{3}) ^ 7\\\\P(C) = \frac{1}{729}

D. The probability is \frac{1}{729}. This number is quite close to zero. Therefore it is an unlikely bastate event.

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1.Write this sentence as an equation.Do not solve it.
Ivahew [28]

Problem 1

x = some unknown number

3x = three times a number

3x-7 = difference of three times a number and seven

2(3x-7) = two times the difference of three times a number and seven

2(3x-7) = x

The last equation is formed because the expression we built up is equal to the original number in question

<h3>Answer:  2(3x-7) = x</h3>

===========================================================

Problem 2

Use the distribution rule to get

3(2x+4)-2x

3*2x+3*4-2x

6x+12-2x

From here, we combine like terms. That means we combine the 6x and -2x to get 4x

So 6x+12-2x simplifies to 4x+12 and not 16x

How did she get 16x? Possibly because she mistakenly thought she could add 4x to 12 to get 16x. This only works if the 12 had x attached to it.

In other words, this is valid:  4x+12x = 16x but this is not 4x+12 = 16x

===========================================================

Problem 3

L = length = horizontal dimension = (d+15) ft

W = width = vertical dimension = (d-3) ft

P = perimeter of the rectangle = 108 ft

P = 2(L+W)

108 = 2(d+15+d-3)

108 = 2(2d+12)

108 = 4d+24

4d+24 = 108

4d = 108-24

4d = 84

d = 84/4

d = 21

The deep end is 21 feet long.

This means the overall horizontal length is d+15 = 21+15 = 36 feet and the the vertical width is d-3 = 21-3 = 18 feet

The overall dimensions of the rectangular pool are 36 ft by 18 ft

<h3>Answer:  d = 21</h3>
7 0
3 years ago
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