Hey guys I need help with this exercise.. can u plz write the whole equation and how u figured it out plz?? 12 points...!!!
1 answer:
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Answer:
AB = 3.9CM ; A = 51° ; C = 39°
Step-by-step explanation:
Base BC = 4.8cm
AC = 6.2cm
Angle B = 90°
Using trigonometry, the length of AB can be obtained thus :
AB^2 = AC^2 - BC^2
AB^2 = 6.2^2 - 4.8^2
AB^2 = 38.44 - 23.04
AB^2 = 15.4
AB = sqrt(15.4)
AB = 3.92 cm
Angle A :
Using :
Sinα = opposite / hypotenus
Sinα = 4.8 / 6.2
Sinα = 0.7741935
α = sin^-1 (0.7741935)
α = 50.73
A = 51° (approximately)
Angle C ;
(A + B + C) = 180 (Sum of angles in a triangle)
51 + 90 + C = 180
141 + C = 180
C = 180 - 141
C = 39°
