Answer:
B
Explanation:
explanation is given in answer
Answer:
The leading strand is copied in the 5' to 3' direction and the lagging strand is copied in the 3 to 5 direction.
Explanation:
1. The original DNA molecule remains intact, although it acts as a template for the formation of a copy that contains two new antiparallel strands. - this is false.
DNA replication is said to be "semi conservative". This is because in making a new DNA molecule, one of the strands is from the original DNA molecule and one is new. This is true for each new molecule produced One DNA molecule makes 2 new molecules, each containing one of the original strands
2. The leading strand is copied in the 5' to 3' direction and the lagging strand is copied in the 3 to 5 direction. This is true. The synthesis of each strand occurs through a distinct mechanism. The leading strand is synthesised 5'-3' (towards the replication fork), and the lagging strand is synthesised from 3'-5', away from the replication fork. T
he leading strand is synthesised continuously using an RNA primer to begin the process. The lagging strand is synthesised discontinuously, with several short primer sequences permitting the synthesis of short fragments (Okazaki fragments) that are later joined by DNA ligase. <em>NB: this is easy to remember if you consider that </em><em>3 lags behind 5</em>
3. Both strands are copied to form Okazaki fragments, which are later annealed by DNA Ligase. This is false. Only the lagging strand replicates to form Okazaki fragments
4. The replication process proceeds on both strands in the same direction, which requires that RNA primers bind to the lagging strand. This is false. The strands are synthesised in different directions
Answer:
The correct option is;
a. 11.21
Explanation:
The chemical equation for the reaction is;
NH₄OH ↔ NH₄⁺ + OH⁻
At the start of the reaction, we have;
NH₄OH ↔ NH₄⁺ + OH⁻
I 0.15 0 0
C 0.15 - x +x +x
The = 1.78 × 10⁻⁵
Therefore, we have;
1.78 × 10⁻⁵ = [NH₄⁺][OH⁻]/NH₄OH = x²/(0.15 - x)
Which gives;
(0.15 - x) 1.78 × 10⁻⁵ = x²
x² + 1.78 × 10⁻⁵x - 2.67× 10⁻⁶ = 0
Factorizing the above equation online, gives;
(x + 0.00164294)(x - 0.00162514) = 0
Therefore;
x = -0.00164294, or x = 0.00162514
We use the positive result, which is x = 0.00162514 = 1.62514 × 10⁻³ = [OH⁻]
Therefore;
pOH = -log[OH⁻] = -log(0.00162514) = 2.789
pH + pOH = 14
Therefore;
pH = 14 - pOH = 14 - 2.789 ≈ 11.21089
The pH of a 0.15 M NH₄OH solution with = 1.78 × 10⁻⁵ = 11.21.
The pH of a 0.15 M NH₄OH solution with = 1.78 × 10⁻⁵ is approximately 11.21
Answer:
The answer is given below.
Explanation:
A tiny difference in a distant enhancer make a blond through DNA Looping.
DNA Looping can bring the enhancer bound by an activator physically closer to the promoter even if the enhancer is located far away along the DNA molecule.
DNA Looping.
When a protein or a set of complex proteins binds to 2 different sites of DNA simultaneously while looping out the interfering DNA.
Important of DNA Looping
- It regulates metabolism of DNA
- it is involved in transcriptional initiation of prokaryotic operons.
True, reddish-yellowish color on pH paper shows acidity