Answer:
x = 170 deg
Step-by-step explanation:
A tangent to a circle is perpendicular to the radius of the circle at the point of tangency. That means that in quadrilateral AOBC, angles A and B are right angles and measure 90 deg.
The sum of the measures of the angles of an n-sided polygon is
(n - 2)180 deg
In this case, n = 4, so
(4 - 2)180 deg = 360 deg
m<A + m<O + m<B + m<C = 360
90 + x + 90 + 10 = 360
x + 190 = 360
x = 170
Answer: 170 deg
Answer:
23
Step-by-step explanation:
Because 23•23=529 so the square root of 529 is 23.
Answer:
1
Step-by-step explanation:
Anything to the power of 0 is 1. <em>So</em>,
1 x 1 = 1
3.01 m/s
This is a simple projectile calculation. What we want is a vertical velocity such that the time the droplet spends going up and going back down to the surface exactly matches the time the droplet takes to travel horizontally 0.800 meters. The time the droplet spends in the air will is:
V*sqrt(3)/2 ; Vertical velocity.
(V*sqrt(3)/2)/9.8 ; Time until droplet reaches maximum height
(V*sqrt(3))/9.8 ; Double that time for droplet to fall back to the surface.
The droplet's horizontal velocity will be:
V/2.
So the total distance the droplet travels will be:
d = (V*sqrt(3))/9.8 * V/2
d = V^2*sqrt(3)/19.6
Let's substitute the desired distance and solve for V
d = V^2*sqrt(3)/19.6
0.8 = V^2*sqrt(3)/19.6
15.68 = V^2*sqrt(3)
15.68/sqrt(3) = V^2
15.68/1.732050808 = V^2
3.008795809 = V
So after rounding to 3 significant figures, the archerfish needs to spit the water at a velocity of 3.01 m/s
Let's verify that answer.
Vertical velocity: 3.01 * sin(60) = 3.01 * 0.866025404 = 2.606736465
Time of flight = 2.606736465 * 2 / 9.8 = 0.531987034 seconds.
Horizontal velocity: 3.01 * cos(60) = 3.01 * 0.5 =
Equation: y= 9x+ (y-intercept)
Step-by-step explanation:
equation in slope-intercept form is y=mx+b. <em>m</em> represents the slope of the line, and <em>b</em> represents the y=intercept, which is where the line crosses the y-axis.
