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3 years ago

5

What is the interquartile range if the data set? 5,911,13,16,16,19,21

1 answer:

max2010maxim [7]3 years ago

7 0

Answer:

Step-by-step explanation:

5,9,11,(13,16),16,19,21

the mean(middle number) = (13 + 16) / 2 = 29/2 = 14.5

Q1 = (9 + 11) / 2 = 20/2 = 10

Q3 = (16 + 19) / 2 = 35/2 = 17.5

interquartile range (IQR) = Q3 - Q1 = 17.5 - 10 = 7.5 <==

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Wat is the answer for this question -x2 + 5x + 24.

Helen [10]

Answer:

31

Step-by-step explanation:

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3 years ago

What is the GCF OF -20v-50

pantera1 [17]

Answer:

The GCF is -10

Step-by-step explanation:

-10 in the highest/largest number that goes into both -20 and -50.

if you have to factor -20v-50 as well it would be:

-10(2v+5)

and to check if that answer is correct, distribute -10 inside the parenthesses:

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3 years ago

Read 2 more answers

Help please now i cant figure it out

12345 [234]

Answer:

a. $\frac{-11}{24}$

b. $\frac{-3}{2} \\$

c. $\frac{31}{7}$

d. $\frac{11}{16}$

11, 3, 31, 11 = code

Step-by-step explanation:

a. $\frac{-1}{6}\\$ * 2 $\frac{3}{4}$ =

2 $\frac{3}{4}$ = $\frac{4*2+3 }{4}$ = $\frac{11}{4}$

$\frac{-1}{6}\\$ * $\frac{11}{4}$ = $\frac{-1*11}{6*4}$ = $\frac{-11}{24}$

b. $\frac{3}{16}$ / $\frac{-1}{8}$ =

$\frac{3}{16}$ * $\frac{8}{-1}$ = $\frac{3*8}{16*-1} \\$ = $\frac{24}{-16}$ = $\frac{-3}{2} \\$

c. $\frac{-31}{56}$ * $\frac{-8}{1}$ = $\frac{31}{7}$ (you can reduce 8 & 56 by dividing by 8: 56/8=7 & -8/8= -1)

d. 1 $\frac{7}{8}$ / 2 $\frac{8}{11}$ =

1 $\frac{7}{8}$ = $\frac{8*1+7}{8}$ = $\frac{15}{8}$

2 $\frac{8}{11}$ = $\frac{11*2+8}{11}$ = $\frac{30}{11}$

$\frac{15}{8}$ * $\frac{11}{30}$ = $\frac{11}{16}$ (you can reduce 15 & 30 by dividing by 15: 15/15=1 & 30/15 = 2)

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3 years ago

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Answer:53.5 Seconds ;)

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3 years ago

I am being timed. Please help

baherus [9]

Answer:

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Step-by-step explanation:

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3 years ago