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Ivenika [448]
2 years ago
13

Please Help Me as soon as possible

Mathematics
2 answers:
Svetach [21]2 years ago
8 0

Answer:

C

Step-by-step explanation:

Because when the numbers are like that, it doesn't matter if its negative. It'll always be positive. Therfore 9 is greater than 5.

disa [49]2 years ago
3 0

Answer:

B bc 3 would be in between x and 5, and x equals 0

Step-by-step explanation:

hopefully this helped! :)

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Each bottle of perfume contains 2.1 fluid ounces of perfume. The store sells 30 bottles. How many fluid ounces of perfume did th
arsen [322]

Answer:

63

Step-by-step explanation:

8 0
3 years ago
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Janet had 3/5 yd of material. she used 1/3 of it for a hat. How much material did she use? explain how you got your answer.
9966 [12]

Answer:

Think of the total as 1/5 + 1/5 + 1/5 = 3/5

You have THREE fifths of material.

You use ONE of those fifths.

That leaves you with TWO fifths.

Step-by-step explanation:

8 0
3 years ago
Standard deviation measures _____ risk while beta measures _____ risk.
Stolb23 [73]

Answer:

Standard deviation measures Total risk while beta measures Systematic risk.

Step-by-step explanation:

The total risk is the total variability of the portfolio and includes the systematic risk and the unique risk.

The systematic risk is measured by the beta coefficient and it considers the no diversified risk such as changes in the global market. Unique risks are the ones that result from factors specifically related to the company.

3 0
3 years ago
The cost of 2 plates of spaghetti & 1 plate of salad is $27.50. The cost for 4 plates of spaghetti & 3 salads is $59.50.
k0ka [10]

2a+1b=27.50

4a+2b=59.50

Multiply first equation by -4 and the second by 2 so you can drop off the a values then add the equations together.  Then solve for b.  You should get b=6.

Then plug b into one of the original equations and solve for a and you should get 10.75

So a plate of spaghetti is $10.75 and a salad is $6.

<em><u>Please mark brainliest!</u></em>

8 0
3 years ago
Let X denote the amount of time a book on two-hour reserve is actually checked out, and suppose the cdf is the following. F(x) =
Troyanec [42]

Answer:

a) P (x <= 3 ) = 0.36

b) P ( 2.5 <= x <= 3  ) = 0.11

c) P (x > 3.5 ) = 1 - 0.49 = 0.51

d) x = 3.5355

e) f(x) = x / 12.5

f) E(X) = 3.3333

g) Var (X) = 13.8891  , s.d (X) = 3.7268

h) E[h(X)] = 2500

Step-by-step explanation:

Given:

The cdf is as follows:

                           F(x) = 0                  x < 0

                           F(x) = (x^2 / 25)     0 < x < 5

                           F(x) = 1                   x > 5

Find:

(a) Calculate P(X ≤ 3).

(b) Calculate P(2.5 ≤ X ≤ 3).

(c) Calculate P(X > 3.5).

(d) What is the median checkout duration ? [solve 0.5 = F()].

(e) Obtain the density function f(x). f(x) = F '(x) =

(f) Calculate E(X).

(g) Calculate V(X) and σx. V(X) = σx =

(h) If the borrower is charged an amount h(X) = X2 when checkout duration is X, compute the expected charge E[h(X)].

Solution:

a) Evaluate the cdf given with the limits 0 < x < 3.

So, P (x <= 3 ) = (x^2 / 25) | 0 to 3

     P (x <= 3 ) = (3^2 / 25)  - 0

     P (x <= 3 ) = 0.36

b) Evaluate the cdf given with the limits 2.5 < x < 3.

So, P ( 2.5 <= x <= 3 ) = (x^2 / 25) | 2.5 to 3

     P ( 2.5 <= x <= 3  ) = (3^2 / 25)  - (2.5^2 / 25)

     P ( 2.5 <= x <= 3  ) = 0.36 - 0.25 = 0.11

c) Evaluate the cdf given with the limits x > 3.5

So, P (x > 3.5 ) = 1 - P (x <= 3.5 )

     P (x > 3.5 ) = 1 - (3.5^2 / 25)  - 0

     P (x > 3.5 ) = 1 - 0.49 = 0.51

d) The median checkout for the duration that is 50% of the probability:

So, P( x < a ) = 0.5

      (x^2 / 25) = 0.5

       x^2 = 12.5

      x = 3.5355

e) The probability density function can be evaluated by taking the derivative of the cdf as follows:

       pdf f(x) = d(F(x)) / dx = x / 12.5

f) The expected value of X can be evaluated by the following formula from limits - ∞ to +∞:

         E(X) = integral ( x . f(x)).dx          limits: - ∞ to +∞

         E(X) = integral ( x^2 / 12.5)    

         E(X) = x^3 / 37.5                    limits: 0 to 5

         E(X) = 5^3 / 37.5 = 3.3333

g) The variance of X can be evaluated by the following formula from limits - ∞ to +∞:

         Var(X) = integral ( x^2 . f(x)).dx - (E(X))^2          limits: - ∞ to +∞

         Var(X) = integral ( x^3 / 12.5).dx - (E(X))^2    

         Var(X) = x^4 / 50 | - (3.3333)^2                         limits: 0 to 5

         Var(X) = 5^4 / 50 - (3.3333)^2 = 13.8891

         s.d(X) = sqrt (Var(X)) = sqrt (13.8891) = 3.7268

h) Find the expected charge E[h(X)] , where h(X) is given by:

          h(x) = (f(x))^2 = x^2 / 156.25

  The expected value of h(X) can be evaluated by the following formula from limits - ∞ to +∞:

         E(h(X))) = integral ( x . h(x) ).dx          limits: - ∞ to +∞

         E(h(X))) = integral ( x^3 / 156.25)    

         E(h(X))) = x^4 / 156.25                       limits: 0 to 25

         E(h(X))) = 25^4 / 156.25 = 2500

8 0
3 years ago
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