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inessss [21]
3 years ago
10

Calculate the circumference of the circle. Round to the nearest tenth.

Mathematics
1 answer:
Mariulka [41]3 years ago
3 0

Answer:

125.7 mm

Step-by-step explanation:

Circumference=πd=π·40≈125.66371 mm

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Parallelogram ABCD has vertices at A(2,-3), B(8,-6), Cl14,-3), and D(8,0)
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Answer:

The correct option is C.

Step-by-step explanation:

The vertices of ABCD are A(2,-3), B(8,-6), C(14,-3), and D(8,0).

Distance formula:

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

The length of sides are

AB=\sqrt{(8-2)^2+(-6+3)^2}=\sqrt{36+9}=\sqrt{45}

BC=\sqrt{(14-8)^2+(-3+6)^2}=\sqrt{36+9}=\sqrt{45}

CD=\sqrt{(8-14)^2+(0-3)^2}=\sqrt{36+9}=\sqrt{45}

AD=\sqrt{(8-2)^2+(0+3)^2}=\sqrt{36+9}=\sqrt{45}

Since length of all sides are equation therefore the given parallelogram cannot be a rectangle.

Slope formula:

m=\frac{y_2-y_1}{x_2-x_1}

Slope of AB is

m_1=\frac{-6-(-3)}{8-2}=\frac{-3}{6}=\frac{-1}{2}

Slope of BC is

m_2=\frac{-3-(-6)}{14-8}=\frac{3}{6}=\frac{1}{2}

Since the slopes of two consecutive sides are not opposite reciprocals, therefore the given parallelogram is a rhombus. Option C is correct.

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