At 0.01 significance level the hypothesis is rejected.
Null Hypothesis (H₀): The sample data occurs purely from chance.
Alternative Hypothesis (H₁): The sample data is influenced by some non-random cause.
If the p-value of the hypothesis test is less than some significance level (e.g. α = .01), then we can reject the null hypothesis and conclude that we have sufficient evidence to say that the alternative hypothesis is true.
Given that,
x = 28
s = 2.9
μ = 31
n = 8
α = 0.01
Then, the Null Hypothesis : H₀ = 31
The Alternate Hypothesis : H₁ < 31
The average number of cigeratte smoker per day is less than 31.
Test Statistics:
t = x -μ / s√n
= 28 - 31/ 2.9√8
= -3/ 8.41
= -0.356
Since the p-value of 0.0046 is less than the significance level of 0.01, the auditor rejects the null hypothesis.
Learn more about Null hypothesis:
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7/6x=140
since variable x is multiplied by 7/6, find x by multiplying by the inverse of 7/6 which is 6/7.
7/6x × 6/7 = 140 × 6/7
x= 120
Answer:
yes
Step-by-step explanation:
Answer:
He needs to use 25.2 pounds to fertilize his lawn.
Step-by-step explanation:
In order to solve this problem we can use a rule of three in such a way that the content of the bag (36 pounds) can cover 10,000 ft² in the same proportion as "x" pounds can cover 7,000 ft², where "x" is the amount of fertilizer he needs to use.
36 pounds -> 10,000 ft²
x pounds -> 7,000 ft²
36/x = 10000/7000
10000*x = 36*7000
x = 36*7000/10000
x = 25.2 pounds
He needs to use 25.2 pounds to fertilize his lawn.
