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Burka [1]
3 years ago
10

A dilation is given by the transformation (x, y) - (.75x, 75y). What type of dilation is this

Mathematics
1 answer:
uranmaximum [27]3 years ago
3 0
Most likely B because x>1 = enlargement vs x<1 = reduction, & the x & y are doing two completely different things
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Needed ASAP! Please help!
Strike441 [17]

Answer:

the answer is B

Step-by-step explanation: i added the two fractions

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Laticia randomly selected 25% of the seventh grade students in her school and asked them their favorite season. Of the students
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I would say 75 or 150
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Javier used the equivalent ratios to find the number of millimeters in 8 inches. StartFraction 8 inches Over question mark milli
joja [24]

Answer:

203.20 millimeters

Step-by-step explanation:

StartFraction 8 inches Over question mark millimeters EndFraction = StartFraction 40 inches Over 1,016 millimeters

8 inches / ? Millimeters = 40 inches / 1,016 millimeters

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7 0
3 years ago
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3 years ago
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What is the simplified version of 3\sqrt{135}
Aleonysh [2.5K]

Answer:

The simplified version of \sqrt[3]{135} is 3\sqrt[3]{5}.

Step-by-step explanation:

The given expression is

\sqrt[3]{135}

According to the property of radical expression.

\sqrt[n]{x}=(x)^{\frac{1}{n}}

Using this property we get

\sqrt[3]{135}=(135)^{\frac{1}{3}}

\sqrt[3]{135}=(27\times 5)^{\frac{1}{3}}

\sqrt[3]{135}=(3^3\times 5)^{\frac{1}{3}}

\sqrt[3]{135}=(3^3)^{\frac{1}{3}}\times (5)^{\frac{1}{3}}      [\because (ab)^x=a^xb^x]

\sqrt[3]{135}=3\times \sqrt[3]{5}     [\because \sqrt[n]{x}=(x)^{\frac{1}{n}}]

\sqrt[3]{135}=3\sqrt[3]{5}

Therefore the simplified version of \sqrt[3]{135} is 3\sqrt[3]{5}.

7 0
3 years ago
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