The limit from 1 to 2 of the given antiderivative is; -0.19865
<h3>What is the Limit of the Integral?</h3>
We are given the antiderivative of f(x) as sin(1/(x² + 1)). Thus, to find the limit from 1 to 2, we will solve as;
⇒ (sin ¹/₅) - (sin ¹/₂)
⇒ 0.19866 - 0.47942
⇒ -0.19865
Complete Question is;
If sin(1/(x² + 1)) is an anti derivative for f(x), then what is the limit of f(x)dx from 1 to 2?
Read more about integral limits at; brainly.com/question/10268976
I think the answer is C.40
The function shown in the graph in the image attached below is 
.
<u>Given the following data:</u>
- Points on the x-axis = (0, 4)
- Points on the y-axis = (0, 4)
First of all, we would determine the slope of this line by using the following formula;
Substituting the points into the formula, we have;
Slope, m = 1
Next, we would find the intercept:
Let x = 0, for the y-intercept.
b = 4
Therefore, the function shown in the graph in the image attached below is
Read more on slope here: brainly.com/question/3493733
The statement that is true of simon as an individual is; C: His annual deductible will be $800.
<h3>What is In-network Insurance?</h3>
For in - network insurance, we know the following facts;
- Charged a lower copayment rate after deductible.
- Incur a relatively low out-of-pocket amount.
- Have a relatively low annual deductible.
Now, in-network physicians help to reduce the cost of insurance to the individual and as a result, what is most likely going to happen is that Simon will have an annual deductible of $800 and is less likely that he will not pay anything after meeting this annual deductible.
The missing options are;
a. The cost of his annual physical will be 50% after deductible
b. The maximum amount that he can expect to pay out-of-pocket is $6,000.
c. His annual deductible will be $800.
d. Once he hits his annual deductible of $800, he will incur no additional costs for health care services for the rest of the calendar year.
Read more about in-network insurance at; brainly.com/question/26278533
