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Vlad1618 [11]
2 years ago
12

What are some ways that drugs and alcohol can impair drivers? check all that apply.

SAT
1 answer:
malfutka [58]2 years ago
4 0
Can you show the options?
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All animals need to eat blank to get blank to live
DerKrebs [107]

Answer:

Food

Explanation:

I mean what else would it be?

4 0
2 years ago
Read 2 more answers
Andrew would like a career selling policies to people to protect their homes against damage from natural disasters. Which pathwa
artcher [175]

Answer:

Insurrance

Explanation:

hes protecting their homes from natural cuases

4 0
3 years ago
John bought 15 pines for $3500
Shalnov [3]

Answer:

Explanation:

If John needs to ensure a 40% profit, John needs to sell the pines at a price that would give 40% more money back than he spent.

Since John needs to make back all of the money he spent, plus another 40%, John needs to get back 140% of what he spent.

140\% = 1.40

John spent $3500.

140% of $3500 is $4900.

So, John must bring in $4900 (revenue) selling all 15 pines to achieve a 40% profit.

However, the question asks for the price of a single pine.  To find the unit price of a single pine, divide the total revenue by 15.

\frac{\$4900}{15pines}=\frac{\$326.\bar{6}}{pine}=\$326.66 \text{ per pine}

6 0
2 years ago
If m is the center of a semi circle what is the perimeter of the figure shown above?
salantis [7]

Answer:

D

Explanation:

add all the know sides 8+8+3+5=24

perimeter of half a semicircle=circumference of half a semicircle

if circle is C=π×d

than semi C=1/2×d×π

C=½×4×π

C=2pi

so 24+2pi

7 0
3 years ago
Joan conducted a study to see how common binge drinking is on her college campus. She defined “frequent binge drinking” as havin
NeX [460]

Answer:

I used the function 1-proportion z-interval on the calculator, where I inputted

  • Successes(x) = 64
  • Sample size(n) = 593
  • Confidence Level(C level) = 0.99

It would result in zInterval_1Prop 64,593,0.99: stat.results, where the values are shown below as:

  • Lower bound (CLower) = 0.075105
  • Upper bound (CUpper) = 0.140747
  • test statistic (p^) = 0.107926
  • Margin of error (ME) = 0.032821

Therefore, the 99% confidence interval would be around 0.11 ± 0.03 or range from 0.08 to 0.14.

<em><u>Note: not sure if this is correct</u></em><em> O_o</em>

3 0
3 years ago
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