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ludmilkaskok [199]
3 years ago
5

Un balón de fútbol que se patea aun angulo de 45° con la horizontal, recorre 30m antes de chocar contra el suelo encuentre, la r

apidez inicial del balón,el tiempo que permanece en el aire, la altura máxima que alcanza
Mathematics
1 answer:
Mamont248 [21]3 years ago
4 0

Responder:

Explicación paso a paso:

El movimiento de la pelota es un movimiento de proyectil ya que se permite que el objeto caiga libremente bajo la gravedad.

Según el rango, el rango del objeto es la distancia cubierta por el objeto en la dirección horizontal.

Rango = U²sin2theta / g

U es la velocidad inicial de la pelota

theta es el ángulo de lanzamiento

g es la aceleración debido a la gravedad

Rango dado = 30 m

Theta = 45 °

Podemos obtener la velocidad inicial del objeto sustituyendo los valores dados en la fórmula

30 = u²sin2 (45 °) /9.81

30 = u²sin90 ° / 9.81

Multiplicación cruzada

294.3 = u²

U = √294.3

U = 17.16 m / s

La velocidad inicial de la pelota es 17.16m / s

- El tiempo que la pelota pasó en el aire es su tiempo de vuelo.

Tiempo de vuelo = 2Usintheta / g

T = 2 (17.16) sen45 ° / 9.81

T = 24.27 / 9.81

T = 2.47 segundos

El tiempo que la pelota pasó en el aire es 2.47 segundos

- La altura máxima de la pelota se expresa como se muestra.

Altura máxima = U²sin²theta / 2g

Altura máxima = 17.16² (sin45 °) ² / 2 (9.81)

Altura máxima = 147.23 / 19.62

La altura máxima alcanzada por la pelota es 7.50m

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40 grams of 13% alcohol solution and 10 grams of 18% alcohol solution.

Step-by-step explanation:

13%(x) + 18%(50-x) = 14%*50g   Multiply them all

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0.13x-0.18x + 9 = 7   Simplify the equation and subtract 0.13x from 0.18x

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Your welcome

4 0
3 years ago
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What is 3 3/5 ÷ 1 4/5 =
Marysya12 [62]

Answer:

2

Step-by-step explanation:

3 3/5 : 1 4/5= 2/1 = 2

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Find the percent of the area under the density curve where x is more than 3. <br>​
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Answer:

The percent of the area under the density curve where x is more that 3 is 25 %.

Step-by-step explanation:

Since the density curve is a linear function, the area under the curve can be calculated by the geometric formula for a triangle, defined by the following expression:

A = \frac{1}{2}\cdot (x_{f} - x_{o})\cdot  (y_{f}-y_{o}) (1)

Where:

A - Area, in square units.

x_{f} - x_{o} - Base of the triangle, in units.

y_{f} - y_{o} - Height of the triangle, in units.

The percent of the area is the ratio of triangle areas under the density curve multiplied by 100 per cent, that is:

x = \frac{\frac{1}{2}\cdot (5-3)\cdot (0.25) }{\frac{1}{2}\cdot (5-1)\cdot (0.5) }\times 100\,\%

x = 25\,\%

The percent of the area under the density curve where x is more that 3 is 25 %.

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3 years ago
Objects A and B are in harmonic motion modeled by
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Answer:

The phase difference between yA and yB is  \frac{-\pi }{12}

Step-by-step explanation:

Given harmonic modeled as :

yA = 8 sin(2t  - \frac{\pi }{3})         And

yB = 8 sin(2t  - \frac{\pi }{4})

The function as written as :

y = a sin(ωt  - Ф)  where  Ф is phase difference

So , phase difference between yA   and  yB = ( Ф_1 - Ф_2 )

Or phase difference between yA   and  yB = ( -  \frac{\pi }{3} + \frac{\pi }{4} )

Or, phase difference between yA   and  yB = (\frac{-4\pi +3\pi }{12})

I.e phase difference between yA   and  yB =\frac{-\pi }{12}

Hence The phase difference between yA and yB is \frac{-\pi }{12}   Answer

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