Help me please Solve the inequality s: 5s+2>7

Solve for the given variable 7x+5y=6 for y

olga_2 [115]

Answer:

y = (6/5) - (7/5) x

Step-by-step explanation:

goal: to rearrange the equation such that it takes the form:

y = f(x) ; where f(x) is an expression in terms of x

Given:

7x+5y=6 subtract 7x from both sides

5y = 6 - 7x (divide both sides by 5)

y = (6-7x) / 5

y = (6/5) - (7/5) x

4 0

2 years ago

. Lightning Strikes It has been said that the probability of being struck by lightning is about 1 in 750,000, but under what cir

mrs_skeptik [129]

Complete Question

The complete question is shown on the first uploaded image

Answer:

a

$P(U |D ) = 0.198$

b

$P(O\ n \ B) = 0.188$

c

$P(O | B) = 0.498$

Step-by-step explanation:

The total number of deaths is mathematically represented as

$T = 16 + 23 + \cdots + 16$

$T =623$

The total number of deaths in 1996 - 2000 is mathematically represented as

$T_a = 16 + 23+ \cdots + 30$

$T_a = 235$

The total number of deaths in 2001 - 2005 is mathematically represented as

$T_b = 17 + 16 + \cdots + 23$

$T_b = 206$

The total number of deaths in 2006 - 2010 is mathematically represented as

$T_c = 15 + 17 + \cdots + 16$

$T_d = 182$

Generally the the probability that it would occur under the tree given that the death was after 2000 is mathematically represented as

$P(U |D ) = \frac{P(A \ n\ U )}{P(A)}$

Here $P(A \ n\ U )$ represents the probability that it was after 2000 and it was under the tree and this is mathematically represented as

$P(A \ n\ U ) = \frac{Z}{ T}$

Here Z is the total number of death under the tree after 2000 and it is mathematically represented as

$Z = 35 + 42$

=> $Z = 77$

=> $P(A \ n\ U ) = \frac{77}{ 623}$

=>

Also

$P(A)$ is the probability of the death occurring after 2000 and this is mathematically represented as

$P(A) = \frac{T_b + T_c}{ T}$

=> $P(A) = \frac{ 206+ 182}{623}$

=>

So

$P(U |D ) = \frac{\frac{77}{ 623} }{ \frac{ 206+ 182}{623}}$

=> $P(U |D ) = 0.198$

Generally the probability that the death was from camping or being outside and was before 2001 is mathematically represented as

$P(O | B) = \frac{T_z}{ T}$

Here $T_z$ is the total number of death outside / camping before 2001 and the value is 117

So

$P(O \ n \ B) = \frac{117}{623}$

=> $P(O\ n \ B) = 0.188$

Generally the probability that the death was from camping or being outside given that it was before 2001 is mathematically represented as

$P(O | B) = \frac{ P( O \ n \ B)}{ P(B)}$

Here $P(B)$ is the probability that it was before 2001 , this is mathematically represented as

$P(B ) = \frac{T_a}{T}$

=> $P(B ) = \frac{235}{623}$

So

$P(O | B) = \frac{ \frac{117}{623}}{ \frac{235}{623}}$

=> $P(O | B) = 0.498$

5 0

3 years ago

A tank full of water is leaking at a constant rate for 30 minutes. The equation

ankoles [38]

Answer: A. There were 500 liters in the tank when the leak started, and it is decreasing by 9 liters per minute.

Step-by-step explanation:

This equation is in the form; y =mx + c.

c in this equation is the value of y when x is at 0.

c in the above formula is 500 which means that the number of litres (y) at zero minutes(x) is 500 litres.

m is the rate of change as a result of a change in x.

m in this equation is -9 which means that the water is reducing by 9 litres every minute (x).

3 0

2 years ago

you deposit 1,750 into an interestmemt account that will produce 6.05% annual interest the money was left in the account for 2 y

Ymorist [56]

Answer:

i dont know mabey someone else knows

5 0

2 years ago

Someone pls help me with this it’s not cut off this time but pls help me

stealth61 [152]

It’s A “9/14”
Explanation:
3/4 is bigger than 9/14
If you graph those two fractions, you can clearly see that 9/14 is one number/block less than 3/4. Hope this helped!

5 0

3 years ago