Problem 1.3

I don’t get it I need help solving this math problem I

harkovskaia [24]

Answer:

Step-by-step explanation:

you know the total angle is 180° from A to D

and you know that ∠BEC is 90°

also you are told that ∠CED is 18°

and that ∠AEB is 4x°

so just put that all together

180=90 + 18 +4x

now solve for X

180-90-18=4x

72=4x

18 = x

so now you know X

now solve ∠AEB

4(18) = 72°

∠AEB= 72°

:)

6 0

3 years ago

Subtract-3x - 8 from 4x² - 7x - 2.

allsm [11]

$( {4x}^{2} - 7x - 2) - (3x - 8) \\ \\ {4x}^{2} - 7x - 2 - 3x + 8 \\ \\ {4x}^{2} - 10x + 4.$

3 0

2 years ago

M<1 =40-4x; and m<2=50-8x

matrenka [14]

What's the question?

6 0

3 years ago

A personnel director in a particular state claims that the mean annual income is the same in one of the state's counties (Coun

Shalnov [3]

Answer:

a) The hypothesis that the mean annual income is the same could not be rejected. There is no enough evidence to claim they are different.

b) The critical values for this two-sided test are t=±1.711.

Step-by-step explanation:

The question is incomplete:

(a) Identify the claim and state H0 and Ha.

Which is the correct claim below?

(b) Find the critical value(s) and identify the rejection region(s).

Enter the critical value(s) below.

We have an hypothesis test on the difference of two means.

The null and alternative hypothesis are:

$H_0: \mu_a-\mu_b=0\\\\H_a: \mu_a-\mu_b\neq 0$

The claim of the alternative hypothesis is that the mean annual income is different in County A and County B.

The null hypothesis is that the mean annual income is equal in both counties.

The significance level is α=0.10.

The sample from County A has a mean of S40,400, a s.d. of $8,700 and a sample size of 18 residents.

The sample from County B has a mean of S39,200, a s.d. of $6,000 and a sample size of 8 residents.

The standard error of the difference of means is:

$\sigma_d=\sqrt{\frac{\sigma_a^2}{n_a}+\frac{\sigma_b^2}{n_b}}=\sqrt{\frac{8700^2}{18}+\frac{6000^2}{8}}=\sqrt{8705000}=2950$

The degrees of freedom are:

$df=n_a+n_b-2=18+8-2=24$

Then, the test statistic is:

$t=\frac{\Delta M-\Delta \mu}{\sigma_d} =\frac{(40,400-39,200)-0}{2950} =\frac{1200}{2950}=0.407$

For a statistic t=0.407, and df=24, the P-value is P=0.69. As the P-value is bigger than the significance level, the null hypothesis failed to be rejected.

If we would use the critial value approach, we would have to calculate the critical values for t, for df=24, two sided test and α=0.10.

The critical values, looking in a table, are t=1.711.

5 0

3 years ago

A small motorboat travels 12mph in still water. It takes 2 hours longer to travel 46 miles going upstream than it does going dow

Natasha_Volkova [10]

Using the relation between velocity, distance and time, it is found that the rate of the current is of 3.33 mph.

<h3>What is the relation between velocity, distance and time?</h3>

Velocity is distance divided by time, hence:

v = d/t

A small motorboat travels 12mph in still water. With the current, upstream, 46 miles are traveled in t hours, hence:

12 + r = 46/t

r = 46/t - 12

Downstream, the time is of t + 2 hours, hence:

12 - r = 46/(t + 2)

r = 12 - 46/(t + 2)

Hence, equaling the values for r:

46/t - 12 = 12 - 46/(t + 2)

46/t + 46/(t + 2) = 24

$\frac{46t + 92 + 46t}{t(t + 2)} = 24$

92t + 92 = 24t² + 48t

24t² - 44t - 92 = 0

Using a quadratic equation calculator, the solution is t = 3. Hence the rate is found as follows:

r = 46/t - 12 = 46/3 - 12 = 3.33 mph.

More can be learned about the relation between velocity, distance and time at brainly.com/question/28155966

#SPJ1

4 0

2 years ago