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3 years ago

Answer quick please look at attachment.

Mathematics

2 answers:

Margarita [4]3 years ago

8 0

Answer:

c) KJ and JH

Step-by-step explanation:

hoa [83]3 years ago

4 0

Answer:

lowkey gonna say B

Step-by-step explanation:

shshevr fcfvdbd

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Please help. This is getting confusing. I can mark you brainliest. Please explain it also thank you.

Setler [38]

Answer:

x = 2.5

Step-by-step explanation:

In order to solve for x, we need to write an equation. This question gives us the angles of a triangle, so we can use this to write our equation. All angles of a triangle will always add to 180 degrees, therefore:

(12x+6) + 104 + 40 = 180

Now we can just take out the brackets, combine like terms and isolate and solve for x:

12x + 6 + 104 + 40 = 180

12x + 150 = 180

12x + 150 - 150 = 180 - 150

12x = 30

12x/12 = 30/12

x = 2.5

Hope this helped!

7 0

4 years ago

A kite with a string 50 meters long makes an angle of elevation of 58o with the ground, assuming the string is straight, how hig

joja [24]

String is the hypotenuse
angle is 58 degrees
sine (58) = height / 50
height = 50 * .84805
height = 42.4025

4 0

3 years ago

Henry Can eat 10 corn dogs in one minute. Thomas Can eat 10 corn dogs in 4 minutes. How long does it take them both to eat 25 co

shepuryov [24]

Thomas would take 10 minutes
henry would take 2.5 minutes

6 0

3 years ago

35) -5(6k + 3) - 8(8-4k) = -73

OLga [1]

Answer:

k = 3

Step-by-step explanation:

Step 1: Simplify both sides of the equation.

$-5(6k+3)-8(8-4k)=-73$
$-5(6k) + (-5)(3) + (-8)(8) + (-8)(-4k) = -73$
$-30k-15-64+32k=-73$
$(-30k+32k)+(-15-64)=-73$
$2k-79=-73$

Step 2: Add 79 to both sides.

$2k - 79 + 79 = -73 + 79$

$2k = 6$

Step 3: Divide both sides by 2.

$\frac{2k}2} = \frac{6}{2}$
$k = 3$

8 0

3 years ago

A conical tank (with vertex down) is 10 feet across the top and 12 feet deep. If water is flowing into the tank at a rate of 10

just olya [345]

Answer:

$\frac{dh}{dt}$ ≅ $0.286\frac{ft^{3} }{min}$

Step-by-step explanation:

$V=\frac{\pi }{3}r^{2}h$ ; rate of change $\frac{dV}{dt}=10\frac{ft^{3} }{min}$ , we must find the rate of change of the depth $\frac{dh}{dt} =?;h=8ft$

5h=12r; $V=\frac{\pi }{3}\({\((5h}/12} )} ^{2}h=\frac{\pi }{3}(\frac{25h^{2} }{144})h; V=\frac{25\pi h^{3}}{432}$ ; deriving $\frac{dV}{dt} = \frac{25\pi }{432}(3h^{2})\frac{dh}{dt}$ → $10=\frac{25\pi h^{2}}{144} \frac{dh}{dt}$ → h=8 then $\frac{dh}{dt}=\frac{1440}{25\pi 64}=\frac{9}{10\pi}$ ≅ 0.286 $\frac{ft^{3} }{min}$

3 0

4 years ago