Question

Please help with this

Answer 1

Answer:

A. x = 5, -3

Step-by-step explanation:

The quadratic equation/formula is:

$x = \frac{-b+- \sqrt{b^2 - 4ac} }{2a}$

The setup is:

$ax^2+bx+c=0$

$4x^2 - 8x -60=0$

Plug in the numbers according to the letter associated:

$x = \frac{8+-\sqrt{-8^2-4(4)(-60)} }{2(4)}$

$x = \frac{8+-\sqrt{1024} }{8}$

$x = \frac{8+-32}{8}$

Solve for addition and subtraction:

$x = \frac{8+32}{8}$                                                                              $x = \frac{8-32}{8}$

$x = \frac{40}{8}$                                                                                  $x = \frac{-24}{8}$

x = 5                                                                                      x = -3