B. y = -2 + 4
y = 2 not 5
Answer:
Yes they can all be written in y = mx + b. You just have to move the terms around.
Step-by-step explanation:
y = 2x -3, this is already in slope-intercept form
Now, y - 2 = x + 2: We can add 2 on both sides to cancel out the one on the left side:
y - 2 = x + 2
y - 2 + 2 = x + + 2
y = x + 4 <-- This is in y = mx + b form
Now the last one, 3x = 9 + 3y
We can first divide all terms by 3,
3x = 9 + 3y
/3 /3 /3
x = 3 + y: Then we can subtract 3 from both sides:
x - 3 = 3 + y - 3
x - 3 = y
These are all linear equations because none of the x's have bigger powers than 1. x^2 is a quadratic equation and x^3 is cubic equation.
Can you show the full question?
Answer:
<h2>2.2</h2>
Step-by-step explanation:
Use the cosine law:
We have:
Substitute:
