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Strike441 [17]
3 years ago
12

Help!!!! Measure the angle and classify it as right, acute, or obtuse. <2

Mathematics
1 answer:
nalin [4]3 years ago
4 0

Answer:

B. 25, acute

Step-by-step explanation:

It is acute because it is less than 90°

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Help pls help me!!!!!
Mariulka [41]

Answer:

C

Step-by-step explanation:

This is your answer because when you do the math you get c as your answer.

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pls mark brainly

8 0
3 years ago
Read 2 more answers
X+15= -12<br><br> ASAP!!!!!!!!!!!!!!!!
3241004551 [841]
Subtract 15 on both sides and you get the answer x= -27
3 0
3 years ago
Read 2 more answers
If a kid is 145 cm and he owns an eraser that is 6.8 cm long, 1.5 cm wide, and 1.5 cm tall. If a scientist shoots him with an en
never [62]
To answer this you’d have to use an 2 step equation 145x= 1000
When u get the answer for x multiply the answer by the erasers original area to find the area of the eraser it would be lengthtimes width times height
4 0
3 years ago
A rectangle has the length of 22 inches less than 7 times the width. If the area of the rectangle is 3197 square inches, find th
Nikolay [14]

The length of rectangle is 139 inches

Solution:

Given that, area of the rectangle is 3197 square inches

Let "L" be the length of rectangle and "W" be the width of rectangle

Also given that rectangle has the length of 22 inches less than 7 times the width

Length = 7 times width - 22

L = 7W - 22

<em><u>The area of rectangle is given as:</u></em>

\text {Area of rectangle }=\text { length } \times \text { width }

Substituting the values we get,

\begin{array}{l}{3197=(7 W-22)(W)} \\\\ {3197=7 W^{2}-22 W} \\\\ {7 W^{2}-22 W-3197=0}\end{array}

On solving the above quadratic equation using quadratic formula,

\text {For the quadratic equation } a x^{2}+b x+c=0 \text { where } a \neq 0

x=\frac{-b \pm \sqrt{\left(b^{2}-4 a c\right)}}{2 a}

\begin{array}{l}{\text {Here in } 7 \mathrm{W}^{2}-22 \mathrm{W}-3197=0} \\\\ {a=7 ; b=-22 ; c=-3197}\end{array}

Substituting in above quadratic formula,

\begin{array}{l}{W=\frac{-(-22) \pm \sqrt{\left((-22)^{2}-4(7)(-3197)\right)}}{2 \times 7}} \\\\ {W=\frac{22 \pm \sqrt{90000}}{14}=\frac{22 \pm 300}{14}} \\\\ {W=\frac{22+300}{14} \text { or } W=\frac{22-300}{14}} \\\\ {W=23 \text { or } W=-19.85}\end{array}

Since width of rectangle cannot be negative, ignore negative value of "W"

So width W = 23 inches

Length L = 7W - 22 = 7(23) - 22 = 139 inches

Thus length of rectangle is 139 inches

8 0
4 years ago
The Southside Band marches 1 3/4 miles in an hour in a parade. How far can they march in 5 hours? Multiply. (Enter as an imprope
OlgaM077 [116]
Well you start on the south side of the band and if it works to the 1 to 3 mile ratio then you have your awnser
I hope this helps
8 0
3 years ago
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