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vazorg [7]
3 years ago
12

Find the leg of each isosceles right triangle when the hypotenuse is 5 square root 6

Mathematics
1 answer:
kozerog [31]3 years ago
5 0
Hypotenuse = 5√6

Let the length of each leg be x, since it is Isosceles .

x² + x² = (5√6)²

2x² = (5 * 5 * √6 * √6)

2x² = 150

x² = 150/2

x² = 75

x = √75

x = √(25 * 3)

x = √25 * √3

x = 5√3 
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arsen [322]

Answer:

$13.97  was the price of the dinner b4 tax and tip

Step-by-step explanation:

18.60 - 11% (1.84) = 16.76

16.76 - 20%(2.79) = 13.97

5 0
3 years ago
The relation R is shown below as a list of ordered
Dmitrij [34]

Answer:

(1, 4) and (1,3), because they have the same x-value

Step-by-step explanation:

For a relation to be regarded as a function, there should be no two y-values assigned to an x-value. However, two different x-values can have the same y-values.

In the relation given in the equation, the ordered pairs (1,4) and (1,3), prevent the relation from being a function because, two y-values were assigned to the same x-value. x = 1, is having y = 4, and 3 respectively.

Therefore, the relation is not a function anymore if both ordered pairs are included.

<em>The ordered pairs which make the relation not to be a function are: "(1, 4) and (1,3), because they have the same x-value".</em>

7 0
3 years ago
!!!! PLEASE HELP !!!!!!
Keith_Richards [23]

Answer:

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Step-by-step explanation:

5 0
3 years ago
Solve the given equation by completing the square.
Dmitriy789 [7]

Answer:

a = -4, b = 3 and c = 6 (OR)

a = -4, b = -3 and c = 6

Step-by-step explanation:

x^{2} +8x = 38

Add 16 to both sides.

x^{2} +8x+16 = 38 + 16

(x+4)^{2} =54

x + 4 = \sqrt{54} or x + 4 = -\sqrt{54}

x+4=3\sqrt{6} or x+4=-3\sqrt{6}

x=-4+3\sqrt{6} or x=-4-3\sqrt{6}

Therefore, a = -4, b = 3 and c = 6 (OR)

a = -4, b = -3 and c = 6

6 0
3 years ago
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Step-by-step explanation:

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3 years ago
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