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Elena L [17]
3 years ago
13

Find the first three terms of the sequence below. Tn=n2+2n+9​

Mathematics
1 answer:
klasskru [66]3 years ago
8 0

\\ \bull\tt\longrightarrow T_n=n^2+2n+9

\\ \bull\tt\longrightarrow T_1=1^2+2(1)+9=1+2+9=12

\\ \bull\tt\longrightarrow T_2=2^2+2(2)+9=4+4+9=17

\\ \bull\tt\longrightarrow T_3=3^2+2(3)+9=9+6+9=24

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Step-by-step explanation:

   To find the inverse, we will set f(x) equal to y, swap the x and y values, and then solve for y.

   Given:

f(x) = x² - 25

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x = y² - 25

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   Square root both sides of the equation:

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   Interval notation:

f^{-1}(x)=  \sqrt{x+25},\text{and}\;f^{-1}(x)=  -\sqrt{x+25}

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3 years ago
How many solutions does the following equation have? 12z- 6 + 15z = 27z- 5
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