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Katen [24]
3 years ago
7

Mr. winter has 32 students in his class. he puts 6 student into each group. if Mr winter gives each group five pieces of chart p

aper, how many sheets will he need for the whole class?
PART A. which equation can be used to find the answer?
32-6x5=S
32÷5x6=S
32÷6x5=S
32x6÷5=S

Part B. Complete the statement.

Mr. Winter needs _____ sheets of chart paper.
Mathematics
1 answer:
bagirrra123 [75]3 years ago
4 0

Answer: A) 32÷6x5=S

B) 30 sheets of chart paper.

Step-by-step explanation:

we have 32 students.

he puts 6 students into each group.

he gives each group 5 pieces of chart paper.

32/6 will give us the number of groups

32/6 = 5.33

This means that we have 5 complete groups 6 students, and one group with 2 students. (a total of 6 groups)

And each of these groups need 5 pieces of paper, so we have the equation:

(32/6)*5 = S

and S = 26.66

now, for the 5 complete groups we need 5 pieces of paper for each, and 5*5 = 25 pieces of papper.

For the group of 2 persons we have the oter 1.66 ( or 2 if we round up) pieces of papper.

but this is a group, so they also should receive 5 pieces of papper regardless that they are only 2 integrants, then the total number of paper pieces is 30.

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7 0
3 years ago
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T-shirts are on sale for 35% off. If a T-shirt originally costs 17.40, what is the sale price?
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Answer:

49.7142857143

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3 years ago
A store has been selling 300 Blu-ray disc players a week at $600 each. A market survey indicates that for each $40 rebate offere
timurjin [86]

Answer:

75 $

Step-by-step explanation:

According to problem statement p(300) = 600

And we know that with a rebate of 40 $, numbers of units sold will increase by 80 then if x is number of units sold, the increase in units is

(  x  - 300 )  , and the price decrease

(1/80)*40  =  0,5

Then the demand function is:

D(x)  =  600  - 0,5* ( x - 300 )  (1)

And revenue function is:

R(x) =  x * (D(x)   ⇒   R(x) =  x* [  600  - 0,5* ( x - 300 )]

R(x) = 600*x  - 0,5*x * ( x - 300 )

R(x) = 600*x - 0,5*x² - 150*x

R(x) = 450*x  - (1/2)*x²

Now taking derivatives on both sides of the equation we get

R´(x) =  450  - x

R´(x) =  0       ⇒   450  - x = 0

x = 450 units

We can observe that for   0 < x  < 450  R(x) > 0 then R(x) has a maximum for x = 450

Plugging this value in demand equation, we get the rebate for maximize revenue

D(450)  =  600  - 0,5* ( x - 300 )

D(450)  =  600 - 225 + 150

D(450)  =

D(450)  =  600 - 0,5*( 150)

D(450)  =  600 - 75

D(450)  = 525

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600 - 525  = 75 $

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Makovka662 [10]

Answer:

A

Step-by-step explanation:

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