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Katen [24]
3 years ago
7

Mr. winter has 32 students in his class. he puts 6 student into each group. if Mr winter gives each group five pieces of chart p

aper, how many sheets will he need for the whole class?
PART A. which equation can be used to find the answer?
32-6x5=S
32÷5x6=S
32÷6x5=S
32x6÷5=S

Part B. Complete the statement.

Mr. Winter needs _____ sheets of chart paper.
Mathematics
1 answer:
bagirrra123 [75]3 years ago
4 0

Answer: A) 32÷6x5=S

B) 30 sheets of chart paper.

Step-by-step explanation:

we have 32 students.

he puts 6 students into each group.

he gives each group 5 pieces of chart paper.

32/6 will give us the number of groups

32/6 = 5.33

This means that we have 5 complete groups 6 students, and one group with 2 students. (a total of 6 groups)

And each of these groups need 5 pieces of paper, so we have the equation:

(32/6)*5 = S

and S = 26.66

now, for the 5 complete groups we need 5 pieces of paper for each, and 5*5 = 25 pieces of papper.

For the group of 2 persons we have the oter 1.66 ( or 2 if we round up) pieces of papper.

but this is a group, so they also should receive 5 pieces of papper regardless that they are only 2 integrants, then the total number of paper pieces is 30.

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Answer:

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Step-by-step explanation:

Let the length of the statue's arm be 'x'.

Given:

Height of statue is, H=67\ ft

Height of male is, h=5\ ft\ 9\ in=5\ ft+\frac{9}{12}\ ft=5+0.75=5.75\ ft

Length of the male's arm is, l=27\ in=\frac{27}{12}=2.25\ ft

Now, as the size of Sam Houston's statue is proportional to that of an adult male, therefore, their heights and arm lengths will also be in proportion. So,

\frac{H}{h}=\frac{x}{l}\\x=\frac{H}{h}\times l

Now, plug in the given values and solve for 'x'.

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