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labwork [276]
3 years ago
8

How do you solve for y in the equation 3x+2y=6

Mathematics
1 answer:
vlada-n [284]3 years ago
3 0
X=2 y=0. 3x=6-2y can't remember how to do the rest
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Solve the following simultaneous linear equations by the substitution method.
anyanavicka [17]

Answer:

p = 2 and q = 2

Step-by-step explanation:

hope this helps please like and mark as brainliest

5 0
3 years ago
Rewrite in simplest terms:
tangare [24]

Answer:

If one −5s−7(8s−1): -61s+7

If two −5s−7(8s−1): -112s+14

Step-by-step explanation:

-5s-7(8s-1)

Multiply -7 onto 8s and -1:

-5s-56s+7

add -5s and -56s:

-61s+7

−5s−7(8s−1)−5s−7(8s−1)

Multiply both -7 to 8s and -1

-5s-56s+7-5s-56s+7

add:

-112s+14

6 0
3 years ago
Help math homework both questions
-Dominant- [34]

Answer:

Q-12 The vertical length of the top part of elevator to ground is 0.8484 meters .

Q -14 The glide runway path is 24,752.47 feet .

Step-by-step explanation:

Q - 12

Given as :

The diagonal length of the elevator = e = 1.2 meters

The vertical length of the top part of elevator to ground = x meters

The angle made by elevator with ground = Ф = 45°

<u>Now, According to figure</u>

Sin angle = \dfrac{\textrm perpendicular}{\textrm hypotenuse}

Or, Sin Ф = \dfrac{\textrm x}{\textrm e}

Or, Sin 45° =  \dfrac{\textrm x meters}{\textrm 1.2 meters}

Or, 0.707 × 1.2 meters = x

∴ x =  0.8484 meters

So, The vertical length of the top part of elevator to ground = x = 0.8484 meters

Hence,The vertical length of the top part of elevator to ground is 0.8484 meters .  Answer

Q-14

Given as:

The altitude of decent of plane = H = 10,000 feet

The angle of descend =  Ф = 22°

Let the glide runway path = y feet

<u>Now, According to question</u>

Tan angle = \dfrac{\textrm perpendicular}{\textrm base}

Or, Tan Ф = \dfrac{\textrm H}{\textrm y}

Or, Tan 22° =  \dfrac{\textrm  10,000 feet}{\textrm y feet}

Or, 0.4040 =  \dfrac{\textrm  10,000 feet}{\textrm y feet}

Or, y =  \dfrac{\textrm  10,000 feet}{\textrm 0.4040}

∴   y = 24,752.47

So,The glide runway path = y = 24,752.47 feet

Hence, The glide runway path is 24,752.47 feet . Answer

6 0
3 years ago
A plane traveled 2565 miles with the wind in 4.5 hours and 2205 miles against the wind in the same amount of time. Find the spee
kherson [118]

Answer:

  • plane: 530 mi/h
  • wind: 40 mi/h

Step-by-step explanation:

Let p and w represent the speeds of the plane and the wind. The relation between time, speed, and distance is ...

  speed = distance/time

  p +w = (2565 mi)/(4.5 h) = 570 mi/h

  p -w = (2205 mi)/(4.5 h) = 490 mi/h

Adding these speeds, we get ...

  (p +w) +(p -w) = (570) +(490) mi/h

  2p = 1060 mi/h

  p = 530 mi/h

Then the speed of the wind is ...

  w = 570 mi/h -p = (570 -530) mi/h = 40 mi/h

The plane's speed is 530 mi/h; the wind speed is 40 mi/h.

7 0
2 years ago
A student is asked to find the length of the hypotenuse of a right triangle. The length of one leg is 36 ​centimeters, and the l
DochEvi [55]

Answer:

45.6 cm

Step-by-step explanation:

Let X be the hypotenuse.

(36)^2 + (28)^2 = X^2

X = 45.6 cm

3 0
2 years ago
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