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4 years ago

A town map has a scale of 2cm:0.5km what is the actual distance for a walk measured at 9cm on the map?

Mathematics

2 answers:

lys-0071 [83]4 years ago

6 0

Answer:

2.25 km

Step-by-step explanation:

Since 2 cm represents 0.5 km on the ground we cross multiply to find how much ground will be represented by 9 cm on the map

2cm=0.5km

9cm=?

(9cm×0.5km)÷2cm

4.5km(cm)÷2cm
2.25 km

NOTE: since the cm are the same they will cancel each other out in the division stage

Nastasia [14]4 years ago

4 0

Answer: 2.25 km

Step-by-step explanation:

2 cm = 0.5 km

9 cm = (9 x 0.5)/2

= 2.25 km

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Answer:

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Step-by-step explanation:

Since $y=e^{5t}$ is a solution, then it must satisfy the differential equation. So, we calculate the derivatives and replace the value in the equation. We have that

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Then, replacing the derivatives in the equation we have:

$25e^{5t}-11(5)e^{5t}+ke^{5t}=0 e^{5t}(25-55+k) =0$

Since $e^{5t}$ is a positive function, we have that

$25-55+k = 0 \rightarrow k = 30$ .

Now, consider a general solution $y(t) = Ae^{rt}, A \in \mathbb{R}$ , then, by calculating the derivatives and replacing them in the equation, we get

$Ae^{rt}(r^2-11r+30)=0$

We already know that r=5 is a solution of the equation, then we can divide the polynomial by the factor (r-5) to the get the other solution. If we do so, we get that (r-6)=0. So the other solution is r=6.

Therefore, the general solution is

$y(t) = C_1e^{5t}+C_2e^{6t}$

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3 years ago

If the cost of 10 tables is $750. Find the number of tables that can be purchased with $8250.

Luden [163]

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3 years ago

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Taya2010 [7]

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