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2 answers:
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Answer:
Proved
Step-by-step explanation:
Given: EC || AC, DB || AC, ∠A = ∠F
Prove: ΔMDF ∼ ΔNCA
Solution
See diagram attached to the solution to better understand the following workings.
Redrawing ΔMDF or rotating to be facing the same direction.
EC is parallel to AC
DB parallel to AC
Using similar triangle theorem:
If ΔMDF ∼ ΔNCA
Ratio of Corresponding sides would be equal
(adjacent of ΔMDF)/(adjacent of ΔNCA) = (Opposite of ΔMDF)/(opposite of ΔNCA) = (hypotenuse of ΔMDF)/(hypotenuse of ΔNCA)
DF/ CA = MD/NC = FM/AN
∠A = ∠F
∠M = ∠N
∠D = ∠C
Since the ratio of Corresponding sides and angle are equal, ΔMDF is similar to ΔNCA.
ΔMDF ∼ ΔNCA
Answer:
The area of the smaller triangle is 75.
Step-by-step explanation:
Here, the ratio of the sides of the similar triangle are 5 : 6
The area if the larger triangle = 108
let us assume that the area of the smaller triangle = m
By the Theorem:
In two similar triangles, the ratio of the areas of similar triangles is the square of the ratio of their sides.
Similarly, here
= \frac{m}{108}[/tex]
⇒
or,
⇒ m = 75
Hence, the area of the smaller triangle is 75.