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Anarel [89]
3 years ago
9

What is the answer to this question plss and thank you

Mathematics
1 answer:
cluponka [151]3 years ago
4 0

A defines the function

f(1) = - 8 ×( \frac{5}{2} )^{0} = - 8 × 1 = -8

f(2) = - 8 ×( \frac{5}{2}) ^{1} = - \frac{(8.5)}{2}= - 20

f(3) = - 8 ×( \frac{5}{2}) ^{2} = - 8 × \frac{25}{4} = - 50

f(4)= - 8 ×( \frac{5}{2}) ^{3} = - 8 × \frac{125}{8} = -125

f(5) = - 8 ×( \frac{5}{2}) ^{4} = - 8 × \frac{625}{16} = - \frac{625}{2}




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Can someone please help me with these? I'm giving 100 points so please.
Cerrena [4.2K]

Answer:

1. -2\frac{9}{12}

2. 10\frac{1}{8}

3. 3

4. -1 > x

Step-by-step explanation:

1.

-\frac{33}{12}  \\12 * 2 = 24\\33 - 24 = 9\\-2\frac{9}{12}

2.

10 \frac{1}{8} / \frac{3}{4} = 13\frac{1}{2} \\13\frac{1}{2} + \frac{1}{2} = 14

3. All share the factor of 3

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3 years ago
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<span>To convert a percentage to a decimal you move the decimal two places to the left. Therefore:

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3 years ago
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If the diameter of a circle has endpoints A (7,2) and B (-1,8), where is the center?
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Math-- Farmer Bill has 500 meters of fencing and wants to enclose a rectangular plot that borders on a river. If farmer Bill doe
bixtya [17]

Answer:

Required dimensions of the rectangle are L = 200 m, W  = 100 m

The  largest area that can be enclosed is 20,000 sq m.

Step-by-step explanation:

The available length of the fencing = 500 m

Now, Perimeter of a rectangle = SUM OF ALL SIDES  = 2(L+B)

But, here once side of the rectangle is NOT FENCED.

So, the required perimeter  

= Perimeter of Complete field - Boundary of 1 open side

= 2(L+ W)   - L  = 2W + L

Now, fencing is given as 500 m

⇒  2W + L  = 500

Now, to maximize the length and width:

put L = 200, W = 100

we get 2(W) +L =  2(200) + 100 = 500 m

Hence, required dimensions of the rectangle are L = 200 m, W  = 100 m

The maximized area = Length x Width

                                   = 200 m x 100  m = 20, 000 sq m

Hence, the  largest area that can be enclosed is 20,000 sq m.

6 0
3 years ago
MT is a diameter of OE. Calculate the measure of ZMTH.
irga5000 [103]

Answer:

A. 17°

Step-by-step explanation:

Recall: measure of an inscribed angle = ½(intercepted arc)

Inscribed angle = m<MTH

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Therefore,

m<MTH = ½(Arc MH)

Substitute

m<MTH = ½(34)

m<MTH = 17°

8 0
3 years ago
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