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2 years ago

I’ve been stuck in this i’ve been thinking it’s 104 but it says it’s not

Mathematics

2 answers:

Luda [366]2 years ago

5 0

Answer:

AD is a diameter, then AFD = 180 deg

BFC = 180 - BFA - CFD = 180 - 57 -76 = 47 deg

BAC = (1/2)BFC = (1/2) x 47 =23.5 deg

Hope this helps!

Ghella [55]2 years ago

5 0

Answer:

313°

Step-by-step explanation:

We want to find the measure of the major arc BAC, which we notice is actually made up of multiple arcs: AED, BA, and CD. So we can write this as:

arc BAC = arc BA + arc AED + arc CD

We already know that arc CD = 76 degrees. We also know that the angle AFB is 57 degrees. Notice that AFB is a central angle, so by definition of central angles and their corresponding arcs, angle AFB is equal to the measure of arc BA. So, arc BA = 57 degrees.

Finally, look at arc AED. This is a semicircle, so by definition, it is 180 degrees. Now plug all these values into the equation:

arc BAC = arc BA + arc AED + arc CD

arc BAC = 57 + 180 + 76 = 313

The answer is 313°.

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Since they are complementary
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2 years ago

At a track meet, Tim ran at a constant speed of 300 meters per minute. After 8 minutes, he still had 600 meters left to run. The

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Okay so 300 meters per minute and he ran 8 minutes..

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2 years ago

Stanley, the skunk, is traveling from point A to point B by taking a shortcut through the pond.A path that avoids the pond is 25

san4es73 [151]

Stanley the skunk will save about 15.5 feet.

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2 years ago

The National Center for Education Statistics surveyed a random sample of 4400 college graduates about the lengths of time requir

Paha777 [63]

Answer:

95% confidence interval for the mean time required to earn a bachelor’s degree by all college students is [5.10 years , 5.20 years].

Step-by-step explanation:

We are given that the National Center for Education Statistics surveyed a random sample of 4400 college graduates about the lengths of time required to earn their bachelor’s degrees. The mean was 5.15 years and the standard deviation was 1.68 years respectively.

Firstly, the pivotal quantity for 95% confidence interval for the population mean is given by;

P.Q. = $\frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }$ ~ N(0,1)

where, $\bar X$ = sample mean time = 5.15 years

$\sigma$ = sample standard deviation = 1.68 years

n = sample of college graduates = 4400

$\mu$ = population mean time

Here for constructing 95% confidence interval we have used One-sample z test statistics although we are given sample standard deviation because the sample size is very large so at large sample values t distribution also follows normal.

So, 95% confidence interval for the population mean, $\mu$ is ;

P(-1.96 < N(0,1) < 1.96) = 0.95 {As the critical value of z at 2.5%

level of significance are -1.96 & 1.96}

P(-1.96 < $\frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }$ < 1.96) = 0.95

P( $-1.96 \times {\frac{\sigma}{\sqrt{n} } }$ < ${\bar X-\mu}$ < $1.96 \times {\frac{\sigma}{\sqrt{n} } }$ ) = 0.95

P( $\bar X-1.96 \times {\frac{\sigma}{\sqrt{n} } }$ < $\mu$ < $\bar X+1.96 \times {\frac{\sigma}{\sqrt{n} } }$ ) = 0.95

95% confidence interval for $\mu$ = [ $\bar X-1.96 \times {\frac{\sigma}{\sqrt{n} } }$ , $\bar X+1.96 \times {\frac{\sigma}{\sqrt{n} } }$ ]

= [ $5.15-1.96 \times {\frac{1.68}{\sqrt{4400} } }$ , $5.15+1.96 \times {\frac{1.68}{\sqrt{4400} } }$ ]

= [5.10 , 5.20]

Therefore, 95% confidence interval for the mean time required to earn a bachelor’s degree by all college students is [5.10 years , 5.20 years].

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3 years ago