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Andre45 [30]
3 years ago
15

Find the area A of triangle JKL with the vertices J(5,8), K(0,7), and L(5,4)

Mathematics
1 answer:
eimsori [14]3 years ago
5 0

Answer:

Area of the triangle is 10 square units

Step-by-step explanation:

Recall that the formula for the area of a triangle is: "base x height / 2", and  in this case, we can consider the triangle's base as the segment that joins the vertices (5, 4) and (5, 8) which gives a segment length of 4 units. The height of the triangle is then the distance between the third vertex (0,7) and the base, which is exactly 5 units. Then the area becomes:

Area = 4 x 5 / 2 = 10 square units.

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Step-by-step explanation:

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Since 35 divided by 2.5 is 14 we can tell both sides TL and LY are greater than KH and CH by a factor of 2.5

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Step-by-step explanation:

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