Question

If you answer a question put the number of the question in your answer. Thanks

Answer 1

Answer:

You'll find the answer below each.

Step-by-step explanation:

1-4 you can use this formula: $V=l*h*w$

1.

$V=l*w*h\\V=(6ft)(4ft)(1ft)\\V=24ft^3$

2.

$V=l*h*w\\V=(2yd)(\frac{1}{2}yd )(2yd)\\V=2yd^3$

3.

$V=l*h*w\\V=(12\frac{1}{2}mm)(3mm)(4mm)\\V=150mm^3$

4.

$V=l*h*w\\V=(2cm)(8.5cm)(2cm)\\V=34cm^3$

5-7 you need these 2 formulas: $A=\frac{bh}{2}$ and $V=Bh$ or you can use one formula which is: $V=\frac{bh}{2}*h$

Let me explain. The first formula is for finding the area of the base of the triangle and the second formula is for finding the volume of the prism using the area previously mentioned. The first h is with respect to the triangle and the second h is with respect to the prism.

5.

$V=\frac{bh}{2}*h\\V=\frac{(8in)(6in)}{2}* 18in\\V=\frac{48in^2}{2}*18in\\ V=48in^2*9in\\V=432in^3$

6.

$V=\frac{bh}{2}*h \\V=\frac{(11m)(5m)}{2}*35m \\V=\frac{55m^2}{2}*35m\\ V=\frac{1925m^3}{2}\\ V=962.50m^3$

7.

$V=\frac{bh}{2}*h \\V=\frac{(5mm)(8mm)}{2}*12mm\\V=\frac{40mm^2}{2}*12mm\\ V=40mm^2*6mm\\V=240mm^3$

For the last one, we have a special case.

This formula is a bit odd and long.

$V=\frac{1}{4}h(\sqrt{-a^4+2(ab)^2+2(ac)^2-b^4+2(bc)^2-c^4}$

a=8yd

b=15yd

c=17yd

h=11yd

$V=\frac{1}{4}(11yd)(\sqrt{-(8yd)^4+2[(8yd)(15yd))]^2+2[(8yd)(17yd)]^2-(15yd)^4+2[(15yd)(17yd)]^2}$$-(17)^4$

As you can see this is long. I'll just jump to the answer.

Answer: $660yd^3$

Answer 2

Answer:

He is correct

Step-by-step explanation: