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WITCHER [35]
3 years ago
12

Hey can anyone pls help me out in dis I will give up 30 points and also will mark u as brainliest!!!!!!!!!!

Mathematics
1 answer:
geniusboy [140]3 years ago
6 0

Answer:

1. f

2. a

3. b

4. e

5. c

6. d

1. I figured out how to order them by using the distance formula to calculate how far each point was, from the other.

2. (1, -10) and (1, -11)

3. (1, -10) and (1, 11)

Step-by-step explanation:

<u>Using Letter A, as example:</u>

To calculate the distance between the points, you use the formula:

d = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

d = \sqrt{(2-2)^2+(10-4)^2}

d = \sqrt{0 + 36}

d = 6

Just do the same thing (plug in the numbers into the formula), and you should be able to get the correct answers.

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The population of a town is increasing at a rate of 6.2% per year. The city council believes they will have to add another eleme
kow [346]

Answer:

The correct solution is "4.6".

Step-by-step explanation:

Given:

Interest rate,

r = 6.2%

or,

 = 0.062

Amount,

A = 100000

Principle,

P = 76000

As we know,

⇒ A=P(1+\frac{r}{100} )^n

On substituting the values, we get

⇒ 100000=76000(1+\frac{6.2}{100} )^n

⇒ (1+0.062)^n=\frac{100}{76}

On taking log both sides, we get

⇒ n \ log_e(1.062)=log_e(\frac{100}{76} )

⇒                   n=\frac{ln(\frac{100}{76} )}{ln(1.062)}

By putting the values of log, we get

⇒                      =4.5622

or,

⇒                      =4.6

5 0
3 years ago
A group of 52 people attend a ball game. There were three times as many men as women in the group. Write and solve a system of e
kkurt [141]

Answer:

lets call the children, c, and call adult, a,

c+a= 52       eq 1: a=52-c

c=3a            eq 2

take a's value from eq 1 and plug it into eq 2

c=3(52-c)

c=156-3c

4c=156

c=39 the number of children that attended the ball game.

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
What is (6p+15)+(10p-9)
Yuliya22 [10]
6p+10p+15-9

16p+6 will be your final answer
6 0
3 years ago
Read 2 more answers
Please show your work. The data modeled by the box plots represents the battery life of two different brand of batteries that Ji
Diano4ka-milaya [45]
(a) Brand X median  = 13
      Brand Y median = 16

Median is the center dot in the shaded box (in blue color). Look at the Time (h) axis for their values. For Brand X it is 13 whereas for the Brand Y it is 16

(b) If we compare their median values we can see that the difference is 3 hours (16-13 = 3). It means that the Brand Y battery will last longer compared to Brand X battery as Brand Y lasts for 16 hours whereas Brand X battery lasts for 13 hours. 
7 0
3 years ago
A rectangle has a length 6 more than it's width if the width is decreased by 2 and the length decreased by 4 the resulting has a
Rashid [163]

Answer:

Length of original rectangle: 11 units.

\frac{\text{Area of original rectangle}}{\text{Area of new rectangle}}=\frac{55}{21}

\text{Perimeter of new rectangle}=20

Step-by-step explanation:

Let x represent width of the original rectangle.  

We have been given that a rectangle has a length 6 more than it's width. S the length of the original rectangle would be x+6.

We have been given that when the width is decreased by 2 and the length decreased by 4 the resulting has an area of 21 square units.

The width of new rectangle would be x-2.

The length of new rectangle would be x+6-4=x+2.

The area of new rectangle would be (x+2)(x-2).

Now we will equate area of new rectangle with 21 and solve for x as:

(x+2)(x-2)=21

Applying difference of squares, we will get:

x^2-2^2=21

x^2-4=21

x^2-4+4=21+4

x^2=25

Since width cannot be negative, so we will take positive square root of both sides.

\sqrt{x^2}=\sqrt{25}

x=5

Therefore, the width of original rectangle is 5 units.

Length of the original rectangle would be x+6\Rightarrow x+5=11.

Therefore, the length of original rectangle is 11 units.

\text{Area of original rectangle}=5\times 11

\text{Area of original rectangle}=55    

Therefore, area of the original rectangle is 55 square units.

Now we will find ratio of the original rectangle area to the new rectangle area as:

\frac{\text{Area of original rectangle}}{\text{Area of new rectangle}}=\frac{55}{21}

We know that perimeter of rectangle is two times the sum of length and width.

\text{Perimeter of new rectangle}=2((x+2)+(x-2))

\text{Perimeter of new rectangle}=2((5+2)+(5-2))

\text{Perimeter of new rectangle}=2(7+3)

\text{Perimeter of new rectangle}=2(10)

\text{Perimeter of new rectangle}=20

Therefore, the perimeter of the new rectangle is 20 units.

7 0
4 years ago
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