The area of the region enclosed by the curves x + y = 1, x - 3 = y, y = √x and x = 0 is 16.815 square units.
<h3>How to determine the area of a region enclosed by four functions</h3>
In this question we must determine the area generated by four functions: three <em>linear</em> functions and a <em>radical</em> function. First, we plot the four functions to determine the required combinations of <em>definite</em> integrals need for calculation:
, where f(x) = √x, g(x) = x - 3 and h(x) = - x + 1.
A = 16.815
The area of the region enclosed by the curves x + y = 1, x - 3 = y, y = √x and x = 0 is 16.815 square units.
<h3>Remark</h3>
The statement reports an inconsistency with at least one function and needs to be modified in order to apply definite integrals in a consistent manner. New form is shown below:
Sketch the region enclosed by the given curves and find its area: (i) x + y = 1, (ii) x - 3 = y, (iii) y = √x, (iv) x = 0.
To learn more on definite integrals: brainly.com/question/14279102
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Answer:
0=8
Step-by-step explanation:
The largest exponent is the degree of the polynomial.
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