Answer:
The answer to the question is;
Then the apparent height of each pole if the tallest pole is 50 feet tall and there is 100 feet between each pole is .
Step-by-step explanation:
To answer the question we have
Let the location of the closest pole = x
Let the height of the closest pole = h feet
Also let the actual height of the pole at location 100×n feet away be 50 feet
Where n = 1, 2, 3, ...∞
Then we have by taking tangent of the similar triangles so formed by the poles
Then h/x = 50/(x +100·n)
Therefore h = 50 × x/(x +100·n) = 50·x ÷(x + 100·n) = feet
The apparent height of each pole if the tallest pole is 50 feet tall and there is 100 feet between each pole is 50·x /(x+100·n) where n is the number of 100 feet further away the pole is e.g when n = 1 we have
h = 50·x /(x+100·1) = 50·x /(x+100)
Answer:
5
Step-by-step explanation:
sqrt[(-8+3)² + (-6+6)²] = 5
Answer:
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Step-by-step explanation:
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Answer:
(4, - 6 )
Step-by-step explanation:
7x - y = 34 ( multiply through by - 1 )
- 7x + y = - 34 ( add 7x to both sides )
y = 7x - 34 → (1)
2x + 3y = - 10 → (2)
substitute y = 7x - 34 into (2)
2x + 3(7x - 34) = - 10
2x + 21x - 102 = - 10
23x - 102 = - 10 ( add 102 to both sides )
23x = 62 ( divide both sides by 23 )
x = 4
substitute x = 4 into (1)
y = 7(4) - 34 = 28 - 34 = - 6
solution is (4, - 6 )