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tangare [24]
3 years ago
8

What kind of line is line A.F?

Mathematics
2 answers:
Ede4ka [16]3 years ago
6 0

Answer:

D: Transversal

Step-by-step explanation:

valentina_108 [34]3 years ago
3 0

Answer:

C) Segment

Step-by-step explanation:

A line segment is a line that is bounded by two distinct end points.

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The largest possible circle is cut out of a square whose side length is 8 feet. What will be the approximate area, in square fee
Lunna [17]

Answer:

=13.73 ft²

Step-by-step explanation:

The diameter of the largest possible circle that can be cut out of  a square is equal to the length of the side of the square.

Therefore the diameter of the circle cut from a square of side 8ft =8ft

r=4ft

Area of the remaining board= Area of square- area of circle

=side²-πr²

=8²-π×4²

=64-16π

=13.73 ft²

6 0
3 years ago
F the angle of elevation from the point on the ground to the top of the tree is 34° and the point is 25 feet from the base of th
Viktor [21]

<u>Given:</u>

The angle of elevation from the point on the ground to the top of the tree is 34° and the point is 25 feet from the base of the tree.

We need to determine the height of the tree.

<u>Height of the tree:</u>

Let the height of the tree be h.

The height of the tree can be determined using the trigonometric ratio.

Thus, we have;

tan \ \theta=\frac{opp}{adj}

Substituting the values, we get;

tan \ 34^{\circ}=\frac{h}{25}

Multiplying both sides by 25, we have;

tan \ 34^{\circ} \times 25=h

 0.6745 \times 25=h

       16.8625=h

Rounding off to the nearest tenth of a foot, we get;

16.9=h

Thus, the height of the tree is 16.9 feet.

Hence, Option B is the correct answer.

7 0
3 years ago
The weight of people in a small town in Missouri is known to be normally distributed with a mean of 186 pounds and a standard de
OleMash [197]

Answer:

the probability that a random sample of 17 persons will exceed the weight limit of 3,417 pounds is 0.0166

Step-by-step explanation:

The summary of the given statistical data set are:

Sample Mean = 186

Standard deviation = 29

Maximum capacity 3,417 pounds or 17 persons.

sample size = 17

population mean =3417

The objective is to determine the probability  that a random sample of 17 persons will exceed the weight limit of 3,417 pounds

In order to do that;

Let assume X to be the random variable that follows the normal distribution;

where;

Mean \mu = 186 × 17 = 3162

Standard deviation = 29* \sqrt{17}

Standard deviation = 119.57

P(X>3417) = P(\dfrac{X - \mu}{\sigma}>\dfrac{X - \mu}{\sigma})

P(X>3417) = P(\dfrac{3417 - \mu}{\sigma}>\dfrac{3417 - 3162}{119.57})

P(X>3417) = P(Z>\dfrac{255}{119.57})

P(X>3417) = P(Z>2.133)

P(X>3417) =1- 0.9834

P(X>3417) =0.0166

Therefore; the probability that a random sample of 17 persons will exceed the weight limit of 3,417 pounds is 0.0166

5 0
3 years ago
Bank A: Monthly fee of $4.95 or no fee if minimum balance is $500 or greater.
Crazy boy [7]

Answer:

A

Step-by-step explanation:

3 0
4 years ago
Find the LCM of 4 and 9<br><br> A. 9<br> B. 35<br> C. 72<br> D. none of the above
Vitek1552 [10]
B is the answer becuase it’s 35 and that should be correct
7 0
3 years ago
Read 2 more answers
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