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3 years ago

Y=|x| (What is the range of this function?)

Mathematics

2 answers:

Whitepunk [10]3 years ago

6 0

Answer:Any number both positive or negative.

Step-by-step explanation:y=(all numbers)

olasank [31]3 years ago

5 0

Answer:

Any number both positive or negative.

y = {all numbers}

Step-by-step explanation:

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If √7 = 2.646, find without using calculator, the value of √0.0007

Varvara68 [4.7K]

Answer:

√0.0007 = 0.02646

Step-by-step explanation:

We know that:

√7 = 2.646

We want to find the value of:

√0.0007

Also we know the relations:

$\frac{\sqrt{x} }{\sqrt{y} } = \sqrt{\frac{x}{y} }$

Then:

$\sqrt{0.0007} = \sqrt{\frac{7}{10,000} }$

We can rewrite this as:

$\sqrt{\frac{7}{10,000} } = \frac{\sqrt{7} }{\sqrt{10,000} } = \frac{2.646}{100} = 0.02646$

4 0

3 years ago

A carnival game involves drawing a card from a deck of 40 cards, replacing it, shuffling the deck, and drawing another

padilas [110]

Answer:

4 tokens.

Step-by-step explanation:

The expected value of a given event is calculated as:

EV = (x₁*p₁ + x₂*p2 + ... + xₙ*pₙ)

Where xₙ is the n-th outcome, and pₙ is its probability.

In this case, our experiment is:

You draw two times.

We have 30 cards with no prize

We have 10 cards with a prize.

A total of 40 cards.

As we draw two times (and the first time we draw a card we put it back in the deck) we can consider the events as independent, so we can find the expected value per draw.

Now we can define:

x₁ = drawing a blank card = 0 tokens

The probability will be equal to the quotient between the number of blank cards and the total number of cards

p₁ = 30/40 = 3/4

x₂ = drawing a prized card = 8 tokens.

The probability will be equal to the quotient between the number of prized cards and the total number of cards:

p₂ = 10/40 = 1/4

Then the expected value per draw is:

EV = ( (3/4)*0 tokens + (1/4)* 8 tokens) = 2 tokens.

And we have two draws, then the expected value of two draws is two times the expected value per draw, this means that the expected value in our case is:

expected value = 2*(2 tokens) = 4 tokens.

The correct option is the first one, counting from the top.

8 0

3 years ago

1 and two-thirds minus 2 and one-third

svetoff [14.1K]

Answer:

The answer is -2/3.

Hope this helps and if you could mark as brainliest. Thanks!

4 0

3 years ago

Read 2 more answers

The height (feet) of an object moving vertically is given by s= (-16t^2)+(208t)+(156), where t is in seconds.

OverLord2011 [107]

Answer:

The object's velocity at t = 7 is -16 ft/s

The maximum height is 832 ft and it occurs when $t=\frac{13}{2}$

Step-by-step explanation:

From the information given, the equation of motion of the object is

$s(t)= -16t^2+208t+156$

For any equation of motion s(t), the instantaneous velocity at time t is given by

$v(t)=\frac{ds}{dt}$

(a) To find the object's velocity at t = 7, you must:

$v(t)=\frac{d}{dt}(-16t^2+208t+156)\\\\v(t)=-\frac{d}{dt}\left(16t^2\right)+\frac{d}{dt}\left(208t\right)+\frac{d}{dt}\left(156\right)\\\\v(t)=-32t+208+0\\\\v(t)=-32t+208$

Next, we evaluate when t = 7

$v(7)=-32(7)+208=-224+208\\\\v(7)=-16$

The object's velocity at t = 7 is -16 ft/s

(b) To find the maximum of a function we always use the derivative of the function and we set it equal zero to find the critical points.

To find the maximum height and when it occurs, we set the velocity function equal to 0 and solve for t.

$-32t+208=0\\\\-32t+208-208=0-208\\\\-32t=-208\\\\\frac{-32t}{-32}=\frac{-208}{-32}\\\\t=\frac{13}{2}$

Next, we substitute this value into the equation of motion to find the maximum height

$s(\frac{13}{2})= -16(\frac{13}{2})^2+208(\frac{13}{2})+156\\\\s(\frac{13}{2})=-676+1352+156)=832$

The maximum height is 832 ft and it occurs when $t=\frac{13}{2}$

6 0

3 years ago

Zoey is having a party for 10 friends.2 If each friend eats 1/2 pounds of chips, how many pounds of chips will Zoey need?

Rasek [7]

Answer: C

Step-by-step explanation: 10 times 1/2

3 0

3 years ago

Read 2 more answers