The answer is a.0.32 km.
The speed that a tsunami can travel is modeled by the equation is s = 356√d.
It is given:
s = 200 km/h
d = ?
Now, let's substitute s in the equation and find d:
s = 356√d
200 = 356√d
√d = 200 ÷ 356
√d = 0.562
Now, let's square both sides of the equation:
(√d)² = (0.562)²
d = (0.562)² = 0.316 ≈ 0.32
Therefore, <span> the approximate depth (d) of water for a tsunami traveling at 200 kilometers per hour is 0.32 km.</span>
Answer:
Step-by-step explanation:
Answer:
c = 6
Step-by-step explanation:
(I'm going to call the unidentified inner angle Henry, 'kay?)
First, we need to find Henry.
64 + Henry = 180
(64 - 64) + Henry = (180 - 64)
Henry = 116
Now to c.
Henry + 32 + 5c + 2 = 180
(116 + 32 + 2) + 5c = 180
(150 - 150) + 5c = (180 - 150)
5c/5 = 30/5
c = 6
9514 1404 393
Answer:
1 mile
Step-by-step explanation:
5 × (1/5 mi) = 5/5 mi = 1 mi
The students ran 1 mile in all.
Answer:
3
x
x
+
y
Step-by-step explanation:
(think about it with a horizontal line between the two numbers)
When using fractions and whole numbers turn the whole numbers into fractions like ---> 3/1
and if their like 3 5/6 (for example) you would multiply the denominator by the whole number ---> 3*6=18 then add what's on the numerator with it. so 18+5=23 which would make it 23/6
Just some tips for making it easier!
Hope it helps! :)
