The scenario can be described using a piecewise function like:
f(x) = 1/x if x < c.
f(x) = x if x = c
f(x) = 1/(x + 73) if x > c.
<h3>
When the value exists but the limit does not?</h3>
Remember that the limit only exists if the limit from left and the limit from the right give the same value.
Then, we can just define a piecewise function of the form:
f(x) = 1/x if x < c.
f(x) = x if x = c
f(x) = 1/(x + 73) if x > c.
Clearly, this is not a continuous function.
Notice that:
So the limits from left and right are different, then:
Does not exist.
If you want to learn more about limits:
brainly.com/question/5313449
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Answer:
The area of △ABC is 2 square units greater than the area of parallelogram GHJK.
Step-by-step explanation:
Wffdfhjjfgjjv is I don't know
5 + 0.33333...
<span>If you don't immediately recognize 0.33333.... as 1/3 (a very common fraction you should memorize), you can do the following. </span>
<span>x = 0.33333... </span>
<span>Multiply that by 10 to shift everything 1 place to the left: </span>
<span>10x = 3.33333... </span>
<span>Now subtract: </span>
<span>10x - x = 3.33333... - 0.33333... </span>
<span>9x = 3 </span>
<span>x = 3/9 </span>
<span>x = 1/3 </span>
<span>Answer: </span>
<span>5 1/3 </span>
<span>P.S. Here's a shortcut way to turn a repeating decimal into a fraction. </span>
<span>1) Take the repeated part and put it over an equivalent number of nines. </span>
<span>Example: </span>
<span>0.57575757... = 57/99 </span>
<span>At that point, see if you can reduce the fraction: </span>
<span>= 19/33 </span>
<span>Another example: </span>
<span>0.123123123... = 123/999 </span>
<span>= 41/333 </span>
<span>So in your example: </span>
<span>5.33333... = 5 + 0.33333... </span>
<span>= 5 + 3/9 </span>
<span>= 5 1/3</span>
19, 12, 3, 6, 18, 20, 4, 4, 8, 12, 16, 20, 10, 1, 7, 8 1. Find the range of the data
german
Answer:
The highest observation =20
The lowest observation = 1
Range of the data = 20-1
= 19(ans)
