Slope = (y2 - y1)/(x2 - x1)
Slope = (6 -0)/(3 - 0)
Slope = 6/3 = 2
Answer
2
Hello from MrBillDoesMath!
Answer:
40
Discussion:
A diagram is always appreciated!
Assuming that
mAOC = mAOB + mBOC =>
108 = (3x + 4) + (8x - 28) => combine common terms
108 = (3x + 8x) + (4 - 28 ) =>
108 = 11x - 24 => add 24 to both sides
132 = 11x =>
x = 132/11 = 12
So mAOB = 3x + 4 = 3(12) + 4 = 36 + 4 = 40
Thank you,
MrB
First, square both sides. This will cancel out the radical.
(a^2 = b + 6)
Then subtract 6 from both sides
b = a^2 - 6
Answer:
9.8
Step-by-step explanation:
Answer:
x = 1, y = 2, z = -1
Step-by-step explanation:
2x + 4y = 10
2x = -4y + 10
x = -2y + 5
now sub -2y + 5 in for x, back into the other 2 equations
2x + 2y + 3z = 3 -3x + y + 2z = -3
2(-2y + 5) + 2y + 3z = 3 -3(-2y + 5) + y + 2z = -3
-4y + 10 + 2y + 3z = 3 6y - 15 + y + 2z = -3
-2y + 3z = 3 - 10 7y + 2z = - 3 + 15
-2y + 3z = - 7 7y + 2z = 12
-2y + 3z = -7....multiply by 2
7y + 2z = 12...multiply by -3
--------------------------
-4y + 6z = -14 (result of multiplying by 2)
-21y - 6z = -36 (result of multiplying by -3)
---------------------------add
-25y = - 50
y = -50/-25
y = 2 <===
2x + 4y = 10 2x + 2y + 3z = 3
2x + 4(2) = 10 2(1) + 2(2) + 3z = 3
2x + 8 = 10 2 + 4 + 3z = 3
2x = 10 - 8 6 + 3z = 3
2x = 2 3z = 3 - 6
x = 2/2 3z = -3
x = 1 <== z = -3/3
z = -1 <===
