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3 years ago

15

Please help me I will give you all my points

2 answers:

Marizza181 [45]3 years ago

4 0

Answer:

likely

Step-by-step explanation:

it is likely because at first there were 3 green marbles and three is more than 2 so at the first draw you probably chose a green one but at the second time they are both equal so it's a 50-50 chance

ankoles [38]3 years ago

3 0

Answer:I am assuming you mean that 2 marbles are picked out of the box. Since we have only 2 yellow marbles the solution the your problem would be

P( we pick 2 yellow marbles)

2/5 x 1/4= 0,10

Step-by-step explanation: Mark me as brainliest

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169= (24/2)^2 +(d/2)^2

OlgaM077 [116]

Answer: d = ±10

<u>Step-by-step explanation:</u>

169 = $(\frac{24}{2})^{2}$ + $(\frac{d}{2})^{2}$

169 = (12)² + $\frac{d^{2}}{4}$

169 = 144 + $\frac{d^{2}}{4}$

25 = $\frac{d^{2}}{4}$

100 = d²

√100 = √d²

±10 = d

6 0

3 years ago

Please prove this........

Crazy boy [7]

Answer: see proof below

<u>Step-by-step explanation:</u>

Given: A + B + C = π → C = π - (A + B)

→ sin C = sin(π - (A + B)) cos C = sin(π - (A + B))

→ sin C = sin (A + B) cos C = - cos(A + B)

Use the following Sum to Product Identity:

sin A + sin B = 2 cos[(A + B)/2] · sin [(A - B)/2]

cos A + cos B = 2 cos[(A + B)/2] · cos [(A - B)/2]

Use the following Double Angle Identity:

sin 2A = 2 sin A · cos A

<u>Proof LHS → RHS</u>

LHS: (sin 2A + sin 2B) + sin 2C

$\text{Sum to Product:}\qquad 2\sin\bigg(\dfrac{2A+2B}{2}\bigg)\cdot \cos \bigg(\dfrac{2A - 2B}{2}\bigg)-\sin 2C$

$\text{Double Angle:}\qquad 2\sin\bigg(\dfrac{2A+2B}{2}\bigg)\cdot \cos \bigg(\dfrac{2A - 2B}{2}\bigg)-2\sin C\cdot \cos C$

$\text{Simplify:}\qquad \qquad 2\sin (A + B)\cdot \cos (A - B)-2\sin C\cdot \cos C$

$\text{Given:}\qquad \qquad \quad 2\sin C\cdot \cos (A - B)+2\sin C\cdot \cos (A+B)$

$\text{Factor:}\qquad \qquad \qquad 2\sin C\cdot [\cos (A-B)+\cos (A+B)]$

$\text{Sum to Product:}\qquad 2\sin C\cdot 2\cos A\cdot \cos B$

$\text{Simplify:}\qquad \qquad 4\cos A\cdot \cos B \cdot \sin C$

LHS = RHS: 4 cos A · cos B · sin C = 4 cos A · cos B · sin C $\checkmark$

7 0

3 years ago

Solve 3(-1)(10-5-2(3))

AleksAgata [21]

The answer should be 3 :)

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A ball is dropped from a height of 100 cm. The rebound heights to the nearest centimeter are 60, 36, 22, .... What is the total

Nataly_w [17]

Answer:

a

Step-by-step explanation:

5 0

3 years ago

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Varvara68 [4.7K]

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3 0

3 years ago