(y+3)(y^2-3y+9)
=y(y^2-3y+9)
+3(y^2-3y+9)
=(y^3-3y^2+9y)+(3y^2-9y+27)
=y^3-3y^2+9y+3y^2-9y+27
=y^3+27
31252130405 is the answer :)
Answer:
ok the anser is 39
Step-by-step explanation:
ypu do bacic equagens
Answer:
A: The interquartile range is 8.
Step-by-step explanation:
Hopefully this helps!
The answer to 1. (1, -2)
The answer to 2. (-2, -2)
The answer to 3. (4, -1/2)
The answer to 4. (3, -1/2)
The answer to 5. No solution.
