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NikAS [45]
2 years ago
15

Please please please.

Mathematics
1 answer:
sesenic [268]2 years ago
4 0
the possibilities are probably b, using the elimination method
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Can I please get some help! thank you!
Lady bird [3.3K]

Answer:

1234?:177997 +1mde explicaciones pero te digo algo es 1 explicasion

3 0
2 years ago
Expand the following:<br> 1/5 (10x-25)
mario62 [17]
<span>This must be your answer:
Expanded: 1/5 x 10x + 1/5 x -25 </span>
3 0
3 years ago
4. Find the range of the data set: 3, 21, 17, 17, 34, 22, 26<br><br>Please help​
Anna007 [38]

Answer:

31

Step-by-step explanation:

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7 0
2 years ago
Read 2 more answers
Mary​'s car will go 261 miles on 14.5 gallons of gasoline in highway driving.
suter [353]

Answer:

a) 91 1/6 gallons

b) 2502 miles

Step-by-step explanation:

You are given a number of miles and a number of gallons for the car. The ratio of these numbers is ...

  (261 mi)/(14.5 gal) = 18 mi/gal

We presume this value is constant for this car. Then the questions can be answered by forming and solving a proportion:

a) 1641 miles/(gallons) = 18 mi/(1 gal)

Multiplying by gallons and dividing by 18 mi/gal, we get

  1641/18 gal = (gallons) = 91 1/6 gal

It will take 91 1/6 gallons of gasoline for Mary to drive to her friend's house.

___

b) Same deal, but the miles are unknown.

  (miles)/(139 gal) = (18 mi)/(1 gal)

Multiplying by 139 gal gives ...

  (18 mi)·139 = (miles) = 2502 mi

139 gallons of gasoline will let Mary drive 2502 miles.

3 0
2 years ago
Plz help me!!!!
sveta [45]
A.) For the Junior Varsity Team, mean would be the appropriate measure of center since the data is <span>symmetric or well-proportioned while we should use standard deviation for getting the measure of spread since it also measures the center and how far the values are from the mean.

b.) For the Varsity Team, the median would be the appropriate measure of the center since the data is skewed left and not evenly distributed so median could be used since it does not account for outliers while we use IQR or interquartile range in measuring the spread of data since IQR does not account for the data that is skewed. </span>
4 0
3 years ago
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