I’m pretty sure it’s miner
“I’ll give you head I mean brainiest”
Please Help! Unit 6: Lesson 1 - Coding Activity 2
Instructions: Hemachandra numbers (more commonly known as Fibonacci numbers) are found by starting with two numbers then finding the next number by adding the previous two numbers together. The most common starting numbers are 0 and 1 giving the numbers 0, 1, 1, 2, 3, 5...
The main method from this class contains code which is intended to fill an array of length 10 with these Hemachandra numbers, then print the value of the number in the array at the index entered by the user. For example if the user inputs 3 then the program should output 2, while if the user inputs 6 then the program should output 8. Debug this code so it works as intended.
The Code Given:
import java.util.Scanner;
public class U6_L1_Activity_Two{
public static void main(String[] args){
int[h] = new int[10];
0 = h[0];
1 = h[1];
h[2] = h[0] + h[1];
h[3] = h[1] + h[2];
h[4] = h[2] + h[3];
h[5] = h[3] + h[4];
h[6] = h[4] + h[5];
h[7] = h[5] + h[6];
h[8] = h[6] + h[7]
h[9] = h[7] + h[8];
h[10] = h[8] + h[9];
Scanner scan = new Scanner(System.in);
int i = scan.nextInt();
if (i >= 0 && i < 10)
System.out.println(h(i));
}
}
Answer:
if (pH<7.0){
neutral=0;
base=0;
acid=1;
}
else if (pH>7.0){
neutral=0;
base=1;
acid=0;
}
else if (pH==7.0){
neutral=1;
base=0;
acid=0;
}
Explanation:
As required by the question, if and else statements have been used to test the value of the pH and assign the apropriate values to the variables neutral, base and acid.
The code snippet below can be used to prompt the user to enter values for pH
<em>import java.util.Scanner;</em>
<em>public class pHTest {</em>
<em> public static void main(String[] args) {</em>
<em> Scanner scr = new Scanner(System.in);</em>
<em> System.out.println("Enter a value for the pH");</em>
<em> int neutral, base, acid;</em>
<em> double pH = scr.nextDouble();</em>
<em> if (pH<7.0){</em>
<em> neutral=0;</em>
<em> base=0;</em>
<em> acid=1;</em>
<em> }</em>
<em> else if (pH>7.0){</em>
<em> neutral=0;</em>
<em> base=1;</em>
<em> acid=0;</em>
<em> }</em>
<em> else if (pH==7.0){</em>
<em> neutral=1;</em>
<em> base=0;</em>
<em> acid=0;</em>
<em> }</em>
<em>} }</em>
Answer:
// here is code in C++
#include <bits/stdc++.h>
using namespace std;
// main function
int main()
{
// variables
int n,no_open=0;
cout<<"enter the number of lockers:";
// read the number of lockers
cin>>n;
// initialize all lockers with 0, 0 for locked and 1 for open
int lock[n]={};
// toggle the locks
// in each pass toggle every ith lock
// if open close it and vice versa
for(int i=1;i<=n;i++)
{
for(int a=0;a<n;a++)
{
if((a+1)%i==0)
{
if(lock[a]==0)
lock[a]=1;
else if(lock[a]==1)
lock[a]=0;
}
}
}
cout<<"After last pass status of all locks:"<<endl;
// print the status of all locks
for(int x=0;x<n;x++)
{
if(lock[x]==0)
{
cout<<"lock "<<x+1<<" is close."<<endl;
}
else if(lock[x]==1)
{
cout<<"lock "<<x+1<<" is open."<<endl;
// count the open locks
no_open++;
}
}
// print the open locks
cout<<"total open locks are :"<<no_open<<endl;
return 0;
}
Explanation:
First read the number of lockers from user.Create an array of size n, and make all the locks closed.Then run a for loop to toggle locks.In pass i, toggle every ith lock.If lock is open then close it and vice versa.After the last pass print the status of each lock and print count of open locks.
Output:
enter the number of lockers:9
After last pass status of all locks:
lock 1 is open.
lock 2 is close.
lock 3 is close.
lock 4 is open.
lock 5 is close.
lock 6 is close.
lock 7 is close.
lock 8 is close.
lock 9 is open.
total open locks are :3
