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2 years ago

Combine like terms. y + 3 + 9(y + 5) =

Mathematics

2 answers:

grin007 [14]2 years ago

8 0

Answer:

10y+48

Step-by-step explanation:

9y+1y= 10y
(9*5)+3=48

Mnenie [13.5K]2 years ago

7 0

Answer:

The answer is 10y + 48.

Step-by-step explanation:

First you have to get rid of brackets by expanding :

$y + 3 + 9(y + 5) \\ = y + 3 + 9y + 45$

Next you have to collect like-terms :

$y + 3 + 9y + 45 \\ = 10y + 48$

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Answer:

19.26

Step-by-step explanation:

7% of 18 is 1.26

1.26+18=19.26

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2 years ago

if MP =5.9, what is RN? round your answer to the nearest tenth. write NA if there is not enough information given.

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2 years ago

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Step-by-step explanation:

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1 year ago

Read 2 more answers

What is the least common denominator for these two rational expressions n^4/n^2+2n+1,7/n^2-8n-9

sergeinik [125]

Answer:

Step-by-step explanation:

n²+2n+1 = (n+1)(n+1)

n²-8n-9 = (n+1)(n-9)

the least common denominator for these two rational expressions is :

(n+1)(n-9)

7 0

2 years ago

In physics, if a moving object has a starting position at so, an initial velocity of vo, and a constant acceleration a, the

emmasim [6.3K]

Answer:

$a=\frac{2S -2v_ot-2s_o}{t^2}$

Step-by-step explanation:

We have the equation of the position of the object

$S = \frac{1}{2}at ^2 + v_ot+s_o$

We need to solve the equation for the variable a

$S = \frac{1}{2}at ^2 + v_ot+s_o$

Subtract $s_0$ and $v_0t$ on both sides of the equality

$S -v_ot-s_o = \frac{1}{2}at ^2 + v_ot+s_o - v_ot- s_o$

$S -v_ot-s_o = \frac{1}{2}at ^2$

multiply by 2 on both sides of equality

$2S -2v_ot-2s_o = 2*\frac{1}{2}at ^2$

$2S -2v_ot-2s_o =at ^2$

Divide between $t ^ 2$ on both sides of the equation

$\frac{2S -2v_ot-2s_o}{t^2} =a\frac{t^2}{t^2}$

Finally

$a=\frac{2S -2v_ot-2s_o}{t^2}$

5 0

2 years ago