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2 years ago

Given L(-4, 3) and M(-7, -2), what is the length of segment LM?

Mathematics

1 answer:

kati45 [8]2 years ago

4 0

Answer:

$d = \sqrt{34}$

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Algebra II

Distance Formula: $d = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Step-by-step explanation:

Step 1: Define

Point L (-4, 3)

Point M (-7, -2)

Step 2: Find distance d

Simply plug in the 2 coordinates into the distance formula to find distance d.

Substitute [DF]: $d = \sqrt{(-7+4)^2+(-2-3)^2}$
Add/Subtract: $d = \sqrt{(-3)^2+(-5)^2}$
Exponents: $d = \sqrt{9+25}$
Add: $d = \sqrt{34}$

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Just two more thanks for all the help thus far

guapka [62]

Answer:

The answer can be calculated by doing the following steps;

Step-by-step explanation:

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3 years ago

Here's the question.

OleMash [197]

Answer:

The value of T₂₀ - T₁₅ is -20.

Step-by-step explanation:

Given :

>> If for an A.P, d = -4

To Find :

>> T₂₀ - T₁₅

Using Formula :

General term of an A.P.

$\star{\small{\underline{\boxed{\sf{\red{ T_n = a + (n - 1)d}}}}}}$

>> Tₙ = nᵗʰ term
>> a = first term
>> n = no. of terms
>> d = common difference

Solution :

Firstly finding the A.P of T₂₀ by substituting the values in the formula :

${\dashrightarrow{\pmb{\sf{ T_n = a + (n - 1)d}}}}$

${\dashrightarrow{\sf{ T_{20} = a + (20 - 1) d}}}$

${\dashrightarrow{\sf{ T_{20} = a + (19)d}}}$

${\dashrightarrow{\sf{ T_{20} = a + 19 \times d}}}$

${\dashrightarrow{\sf{ T_{20} = a + 19d}}}$

${\star \: {\underline{\boxed{\sf{\pink{ T_{20} = a + 19d}}}}}}$

Hence, the value of T₂₀ is a + 19d.

$\rule{190}1$

Secondly, finding the A.P of T₁₅ by substituting the values in the formula :

${\dashrightarrow{\pmb{\sf{ T_n = a + (n - 1)d}}}}$

${\dashrightarrow{\sf{ T_{15}= a + (15 - 1) d}}}$

${\dashrightarrow{\sf{ T_{15}= a + (14) d}}}$

${\dashrightarrow{\sf{ T_{15}= a + 14 \times d}}}$

${\dashrightarrow{\sf{ T_{15}= a + 14d}}}$

${\star{\underline{\boxed{\sf \pink{ T_{15}= a + 14d}}}}}$

Hence, the value of T₁₅ is a + 14d

$\rule{190}1$

Now, finding the difference between T₂₀ - T₁₅ :

${\dashrightarrow{\pmb{\sf{T_{20} - T_{15}}}}}$

${\dashrightarrow{\sf{(a + 19d) - (a + 14d)}}}$

${\dashrightarrow{\sf{a + 19d - a - 14d}}}$

${\dashrightarrow{\sf{a - a + 19d - 14d}}}$

${\dashrightarrow{\sf{0+ 19d - 14d}}}$

${\dashrightarrow{\sf{19d - 14d}}}$

${\dashrightarrow{\sf{5 \times - 4}}}$

${\dashrightarrow{\sf{ - 20}}}$

${\star \: \underline{\boxed{\sf{\pink{T_{20} - T_{15} = - 20}}}}}$

Hence, the value of T₂₀ - T₁₅ is -20.

$\underline{\rule{220pt}{3.5pt}}$

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2 years ago

What is the answer of 10% of 115%

mixer [17]

Answer:

0.115

Step-by-step explanation:

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3 years ago

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A sample of 100 independent random numbers is taken from this distribution, and its average is used to estimate the mean of the

Mariulka [41]

Answer:

The standard error in estimating the mean = (0.1 × standard deviation of the distribution)

Step-by-step explanation:

The standard error of the mean, for a sample, σₓ is related to the standard deviation, σ, through the relation

σₓ = σ/(√n)

n = sample size = 100

σₓ = σ/(√100)

σₓ = (σ/10) = 0.1σ

Hence, the standard error in estimating the mean = (0.1 × standard deviation of the distribution)

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3 years ago

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Aleonysh [2.5K]

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3 years ago