Answer:
Options (a) and (c)
Step-by-step explanation:
There are so many inequalities graphed in the picture attached.
Common area (Triangle shown in the center) of the shaded regions will be the solution of the system of inequalities.
And points lying in this common region will be the solutions.
Points lying in this region are (0, -1) and (0, 0).
Therefore, Options (a) and (c) are the solutions.
So I guess we are solving for x here :)
So here is my work...
a=2x+6xz
Basically I think it would be
a=6xz+2x
WAIT WAIT NO I'M WRONG FORGIVE ME!
It's x=a/2(1+3z)
There are
ways of drawing a 4-card hand, where

is the so-called binomial coefficient.
There are 13 different card values, of which we want the hand to represent 4 values, so there are
ways of meeting this requirement.
For each card value, there are 4 choices of suit, of which we only pick 1, so there are
ways of picking a card of any given value. We draw 4 cards from the deck, so there are
possible hands in which each card has a different value.
Then there are
total hands in which all 4 cards have distinct values, and the probability of drawing such a hand is

Answer:
2
Step-by-step explanation:
Answer:
See sample table below.
Step-by-step explanation:
The function is given as :
f(x) = 3ˣ
A table of values can be formed as ;
x <u>calculations</u> f(x)
-4 3⁻⁴ 0.0123
-3 3⁻³ 0.0370
-2 3⁻² 0.1111
-1 3⁻¹ 0.3333
0 3⁰ 1.000
1 3¹ 3.000
2 3² 9.000
3 3³ 27.00
4 3⁴ 81.00