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3 years ago

Ruth has 6 chores to do. If each chore does not depend on the others, in how many different orders could she do the chores?

Mathematics

2 answers:

Dafna11 [192]3 years ago

7 0

The answer is above you shoukd mark it brainliest

Mice21 [21]3 years ago

3 0

First chore, 6 to choose from.
Second chore, 5 to choose from.
Third chore, 4 to choose from.
Fourth chore, 3 to choose from.
Fifth chore, 2 to choose from.
Sixth chore, 1 to "choose" from.
The total number of orders possible is the product
6*5*4*3*2*1=6!=720

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Animal populations are not capable of unrestricted growth because of limited habitat and food supplies. Under such conditions th

trasher [3.6K]

Answer:

(a) 100 fishes

(b) t = 10: 483 fishes

t = 20: 999 fishes

t = 30: 1168 fishes

(c)

$P(\infty) = 1200$

Step-by-step explanation:

Given

$P(t) =\frac{d}{1+ke^-{ct}}$

$d = 1200\\k = 11\\c=0.2$

Solving (a): Fishes at t = 0

This gives:

$P(0) =\frac{1200}{1+11*e^-{0.2*0}}$

$P(0) =\frac{1200}{1+11*e^-{0}}$

$P(0) =\frac{1200}{1+11*1}$

$P(0) =\frac{1200}{1+11}$

$P(0) =\frac{1200}{12}$

$P(0) = 100$

Solving (a): Fishes at t = 10, 20, 30

$t = 10$

$P(10) =\frac{1200}{1+11*e^-{0.2*10}} =\frac{1200}{1+11*e^-{2}}\\\\P(10) =\frac{1200}{1+11*0.135}=\frac{1200}{2.485}\\\\P(10) =483$

$t = 20$

$P(20) =\frac{1200}{1+11*e^-{0.2*20}} =\frac{1200}{1+11*e^-{4}}\\\\P(20) =\frac{1200}{1+11*0.0183}=\frac{1200}{1.2013}\\\\P(20) =999$

$t = 30$

$P(30) =\frac{1200}{1+11*e^-{0.2*30}} =\frac{1200}{1+11*e^-{6}}\\\\P(30) =\frac{1200}{1+11*0.00247}=\frac{1200}{1.0273}\\\\P(30) =1168$

Solving (c): $\lim_{t \to \infty} P(t)$

In (b) above.

Notice that as t increases from 10 to 20 to 30, the values of $e^{-ct}$ decreases

This implies that:

${t \to \infty} = {e^{-ct} \to 0}$

So:

The value of P(t) for large values is:

$P(\infty) = \frac{1200}{1 + 11 * 0}$

$P(\infty) = \frac{1200}{1 + 0}$

$P(\infty) = \frac{1200}{1}$

$P(\infty) = 1200$

5 0

3 years ago

Find the Area of the figure below, composed of a rectangle and a semicircle. There radius of the circle is shown. Round to the n

DochEvi [55]

Answer: 149.3

Step-by-step explanation:

5 0

3 years ago

Tisha babysat for 5 hours and earned $32.50. At the same rate, how much would she earn in 8 hours?

kolezko [41]

Start by finding her hourly rate. 32.50/5 = 6.5
Next times 6.5 * 8 = 52
Working 8 hours she would make $52
I wish I made that much.

3 0

4 years ago

Read 2 more answers

The table represents an exponential function.

kkurt [141]

Answer:

b=2/3

Step-by-step explanation:

The table is given as:

$\left|\begin{array}{c|c}x&y\\--&--\\1&9\\2&6\\3&4\\4&\dfrac83\\\\5&\dfrac{16}{9}\end{array}\right|$

The exponential function is given in the form

$y= a (b)^{x}$

where a is the initial value and b is the multiplicative rate of change

When x=1, y=9, we have:

$9= a (b)^{1}$

When x=3, y=4, we have:

$4= a (b)^{3}$

Dividing the two equations:

$\dfrac{a (b)^{3}}{a (b)^{1}} =\dfrac{4}{9} \\b^2=\dfrac{4}{9}\\b=\sqrt{\dfrac{4}{9}} \\b=\dfrac{2}{3}$

The multiplicative rate of change, b is 2/3.

5 0

4 years ago

Please help me out, it's a math benchmark, it will be nice, you help me out! Thank you!

Sever21 [200]

The correct answer is c

6 0

3 years ago