All categories

3 years ago

7) What is/are the center,

Mathematics

1 answer:

o-na [289]3 years ago

3 0

Answer:

center: (0,0)

vertices: (-4,0) and (4,0)

foci: (-10.8,0) and (10.8,0)

asymptotes: y = -5/2*x and y = 5/2*x

Step-by-step explanation:

Hyperbola with center as origin general equation is:

x²/a² - y²/b² = 1

Our equation is:

25x² - 4y² = 400

Dividing each term by 400:

25x²/400 - 4y²/400 = 400/400

x²/16 - y²/100 = 1

which matches the general equation. Then, the center is (0,0)

a² = 16

a = 4

b² = 100

b = 10

c² = a² + b²

c = √(16+100) = 10.8

General vertices formula: (±a,0). Replacing, the vertices are: (-4,0) and (4,0)

General foci formula: (±c,0). Replacing, the foci are: (-10.8,0) and (10.8,0)

General asymptotes formula: y = ±b/a*x. Replacing, the asymptotes are:

y = -10/4*x = -5/2*x

y = 10/4*x = 5/2*x

You might be interested in

If you rolled a fair number cube 1-6, 12 times, about how many times would you expect to roll a 5 or a 6?

Sav [38]

Well it is definately not c haha. I would say 3 because it is a pretty even chance of getting three.

4 0

3 years ago

X+5 divided by 3 is less than or equal to 2

hichkok12 [17]

$\frac{x+5}{3} \leq 2$
times both sides by 3
x+5≤6
minus 5 both sides
x≤1

5 0

3 years ago

The table lists how poverty level income cutoffs (in dollars) for a family of four have changed over time. Use the midpoint for

frez [133]

The poverty level cutoff in 1987 to the nearest dollar was $10787.

<h3>How to find a midpoint?</h3>

The midpoint as the point that divides the line segment exactly in half having two equal segments. Therefore, the midpoint presents the same distance between the endpoints for the line segment. The midpoint formula is: $\mathrm{Midpoint\:of\:}\left(x_1,\:y_1\right),\:\left(x_2,\:y_2\right):\quad \left(\frac{x_2+x_1}{2},\:\:\frac{y_2+y_1}{2}\right)$ .

For solving this exercise, first you need plot the points in a chart. See the image.

Your question asks to approximate the poverty level cutoff in 1987 to the nearest dollar using the midpoint formula. Note that the year 1987 is between 1980 and 1990, thus you should apply the midpoint formula from data for this year (1987).

$\mathrm{Midpoint\:of\:}\left(1980,8429),\:\left(1990,13145):\quad \left(\frac{1990+1980}{2},\:\:\frac{13145+8429}{2}\right)\\\\ \\$

$\mathrm{Midpoint\:of\:}\left(1980,8429)\:=\left(\frac{1990+1987}{2},\:\frac{13145+3843}{2}\right)\\ \\ =\left(\frac{3977}{2},\:\frac{21574}{2}\right)$

$\mathrm{Midpoint\:of\:}\left(1980,8429)\:=\=(\frac{3977}{2},10787)$

The answer for your question will be the value that you calculated for the y-coordinate. Then, the poverty level cutoff in 1987 to the nearest dollar was $10787.

Read more about the midpoint segment here:

brainly.com/question/11408596