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Nata [24]
3 years ago
10

laws of Sines with find the angle. Find each measurement indicated. Round your answers to the nearest tenth. Show your work plea

se. Part 2​

Mathematics
1 answer:
Gwar [14]3 years ago
6 0

Answer:

4. Z ≈ 46.1°

5. T ≈ 45.2°

6. F ≈ 15.0°

Step-by-step explanation:

4.

We need to use the Law of Sines, which states that for a triangle with legnths a, b, and c and angles A, B, and C:

\frac{a}{sinA} =\frac{b}{sinB} =\frac{c}{sinC}

Here, we can say that ZY = a = 30, X = A = 110, XY = b = 23, and Z = B. Plug these in to find Z:

\frac{a}{sinA} =\frac{b}{sinB}

\frac{30}{sin(110)} =\frac{23}{sinZ}

Solve for Z:

Z ≈ 46.1°

5.

Use the Law of Sines as above.

\frac{a}{sinA} =\frac{b}{sinB}

\frac{26}{sin(76)} =\frac{19}{sinT}

Solve for T:

T ≈ 45.2°

6.

Again, use the Law of Sines as before.

\frac{a}{sinA} =\frac{b}{sinB}

\frac{29}{sin(137)} =\frac{11}{sinF}

Solve for F:

F ≈ 15.0°

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Given the vertex of a quadratic function, find the axis of symmetry.
motikmotik

(i) The equation of the axis of symmetry is x = - 5.

(ii) The coordinates of the vertex of the parabola are (h, k) = (4, - 18). The x-value of the vertex is 4.

(iii) According to the <em>vertex</em> form of the <em>quadratic</em> equation, the parabola opens down due to <em>negative</em> lead coefficient and has a vertex at (2, 4), which is a <em>maximum</em>.  

<h3>How to analyze and interpret quadratic functions</h3>

In this question we must find and infer characteristics from three cases of <em>quadratic</em> equations. (i) In this case we must find a formula of a axis of symmetry based on information about the vertex of the parabola. Such axis passes through the vertex. Hence, the equation of the axis of symmetry is x = - 5.

(ii) We need to transform the <em>quadratic</em> equation into its <em>vertex</em> form to determine the coordinates of the vertex by algebraic handling:

y = x² - 8 · x - 2

y + 18 = x² - 8 · x + 16

y + 18 = (x - 4)²

In a nutshell, the coordinates of the vertex of the parabola are (h, k) = (4, - 18). The x-value of the vertex is 4.

(iii) Now here we must apply a procedure similar to what was in used in part (ii):

y = - 2 · (x² - 4 · x + 2)

y - 4 = - 2 · (x² - 4 · x + 2) - 4

y - 4 = - 2 · (x² - 4 · x + 4)

y - 4 = - 2 · (x - 2)²

According to the <em>vertex</em> form of the <em>quadratic</em> equation, the parabola opens down due to <em>negative</em> lead coefficient and has a vertex at (2, 4), which is a <em>maximum</em>.  

To learn more on quadratic equations: brainly.com/question/1863222

#SPJ1

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Bob gets 16 problems correct. Hope this helped.
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