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Nata [24]
3 years ago
10

laws of Sines with find the angle. Find each measurement indicated. Round your answers to the nearest tenth. Show your work plea

se. Part 2​

Mathematics
1 answer:
Gwar [14]3 years ago
6 0

Answer:

4. Z ≈ 46.1°

5. T ≈ 45.2°

6. F ≈ 15.0°

Step-by-step explanation:

4.

We need to use the Law of Sines, which states that for a triangle with legnths a, b, and c and angles A, B, and C:

\frac{a}{sinA} =\frac{b}{sinB} =\frac{c}{sinC}

Here, we can say that ZY = a = 30, X = A = 110, XY = b = 23, and Z = B. Plug these in to find Z:

\frac{a}{sinA} =\frac{b}{sinB}

\frac{30}{sin(110)} =\frac{23}{sinZ}

Solve for Z:

Z ≈ 46.1°

5.

Use the Law of Sines as above.

\frac{a}{sinA} =\frac{b}{sinB}

\frac{26}{sin(76)} =\frac{19}{sinT}

Solve for T:

T ≈ 45.2°

6.

Again, use the Law of Sines as before.

\frac{a}{sinA} =\frac{b}{sinB}

\frac{29}{sin(137)} =\frac{11}{sinF}

Solve for F:

F ≈ 15.0°

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Answer:

The  magnitude of the electric force  between these two objects

will be: 181.274 N.

i.e.  F  =181.274 N

Step-by-step explanation:

As

Two object accumulated a charge of  4.5 μC and another a charge of 2.8  μC.

so

q₁ = 4.5 μC = 4.5 × 10⁻⁶ C

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separated distance = d = 2.5 cm

Calculating the magnitude of the force between two charged objects using the formula:

F = \frac{1}{4\pi \epsilon_0}\frac{q_1 q_2}{r^2}

   =\:\frac{4.5\times \:\:10^{-6}\:\times \:\:2.8\:\times \:\:10^{-6}}{4\:\times \:\left(3.14\right)\:\times \:\left(8.85\times \:10^{-12}\right)\times \left(2.5\times \:\:10^{-2}\right)^2}

   =\frac{10^{-12}\times \:12.6}{10^{-12}\times \:4\times \:8.85\pi \left(10^{-2}\times \:2.5\right)^2}        ∵ 4.5\times \:10^{-6}\times \:2.8\times \:10^{-6}=10^{-12}\times \:12.6

   =\frac{10^{-12}\times \:12.6}{10^{-12}\times \:35.4\pi \left(10^{-2}\times \:2.5\right)^2}    ∵ \mathrm{Multiply\:the\:numbers:}\:4\times \:8.85=35.4

\mathrm{Cancel\:the\:common\:factor:}\:10^{-12}

  =\frac{12.6}{35.4\pi \left(10^{-2}\times \:2.5\right)^2}

  =\frac{12.6}{0.025^2\times \:35.4\pi }        ∵ \left(10^{-2}\times \:2.5\right)^2=0.025^2

  =\frac{12.6}{0.022125\pi }        ∵ 35.4\pi\times 0.025^2=0.022125\pi

   =\frac{12.6}{0.06950 }

F  =181.274 N

Therefore, the  magnitude of the electric force  between these two objects will be: 181.274 N.

i.e.  F  =181.274 N

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