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ExtremeBDS [4]
3 years ago
8

18 2/3 divided by 1/3

Mathematics
1 answer:
Elenna [48]3 years ago
8 0

Answer:

56

Step-by-step explanation:

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3(v-3)-7v how to simply this equation
Vadim26 [7]

Answer:

-4v-9

Step-by-step explanation:

Distribute the 3(v-3), we get:

3v-9-7v

Combines like-terms, meaning we combine the numbers with v.

-4v-9

8 0
3 years ago
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20- -4 what is the answer someone tell me
Yanka [14]
The answer is 24!
Calculators help!
6 0
4 years ago
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The areas of the squares adjacent to two sides of a right triangle are 32units^2 and 32 units^2
adoni [48]

Answer:

x = 8 units.

Step-by-step explanation:

I think your question is missed of key information, allow me to add in and hope it will fit the original one.  

<em>The areas of the squares adjacent to two sides of a right triangle are 32 unit square and 32 units square. Find the length,x, of the third side of the triangle</em>

My answer:

  • Let a is the side length of the 1st square

The area of the 1st square is equal to 32 units square

<=> a^{2} = 32

<=> a = 4\sqrt{2} units

  • Let b is the length  of the 2nd  square

The area of the 2nd square is equal to 32 units square

<=> b^{2} = 32

<=> b = 4\sqrt{2} units

  • Find the value of x

Applying the Pythagoras Theorem, we have:

x^{2} = a^{2} + b^{2}

<=> x^{2}  = 32 + 32  

<=> x^{2} = 64

<=> x = 8 units

Hope it will find you well.

4 0
3 years ago
Read 2 more answers
Please Hurry!!
sertanlavr [38]
6/3 = 2
10^4/10^-5 = 10^9

so it's 2 x 10^9

answer
<span>A 2 × 10^9</span>
8 0
4 years ago
Read 2 more answers
Factor this trinomial 4x^2-6x-10 If you can please try to show me how to do it.
lilavasa [31]

Answer:

=2(2x-5)(x+1)

Step-by-step explanation:

So we have the trinomial:

4x^2-6x-10

First, factor out a 2:

=2(2x^2-3x-5)

Now, factor within the parentheses.

To do so, we want to find two numbers. When multiplied, these two numbers must equal (a)(c) and when added, they must equal b

(a)(c) is 2(-5) or -10 and b is -3. So, we want two numbers that when multiplied together gives -10 and when added gives -3.

-5 and 2 works. Therefore:

=2(2x^2-3x-5)

Replace -3x with 2x and -5x:

=2(2x^2+2x-5x-5)

Factor out a 2x for the first two terms. And factor out a negative 5 for the remaining two:

=2(2x(x+1)-5(x+1))

Grouping:

=2(2x-5)(x+1)

And we're done!

8 0
3 years ago
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