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2 years ago

Please can I have help simplifying this Ratio?please sos

Mathematics

2 answers:

natita [175]2 years ago

7 0

Answer:

c) 8 : 3 f) 44 : 1

Step-by-step explanation:

c) Try to reduce the ratio further with the greatest common factor (GCF).

The GCF of 64 and 24 is 8

Divide both terms by the GCF, 8:

64 ÷ 8 = 8

24 ÷ 8 = 3

The ratio 64 : 24 can be reduced to lowest terms by dividing both terms by the GCF = 8 :

64 : 24 = 8 : 3

Therefore:

64 : 24 = 8 : 3

Try to reduce the ratio further with the greatest common factor (GCF).

The GCF of 220 and 5 is 5

Divide both terms by the GCF, 5:

220 ÷ 5 = 44

5 ÷ 5 = 1

The ratio 220 : 5 can be reduced to lowest terms by dividing both terms by the GCF = 5 :

220 : 5 = 44 : 1

Therefore:

220 : 5 = 44 : 1

zhenek [66]2 years ago

6 0

Step-by-step explanation:

c 64:24

divided by 8

8 : 3

D 220 : 5

divided by 5

44 : 1

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Find the area of circle Y. The image is represented by circle Y with a sector XYZ that has an area of 85.5 square meters. That s

pochemuha

Answer:

263.08 m²

Step-by-step explanation:

The fraction of circle area that a sector represents is proportional to the central angle.

<h3>Proportion</h3>

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6 0

1 year ago

Find the exact length of the curve. x=et+e−t, y=5−2t, 0≤t≤2 For a curve given by parametric equations x=f(t) and y=g(t), arc len

Rama09 [41]

The length of a curve C parameterized by a vector function r(t) = x(t) i + y(t) j over an interval a ≤ t ≤ b is

$\displaystyle\int_C\mathrm ds = \int_a^b \sqrt{\left(\frac{\mathrm dx}{\mathrm dt}\right)^2+\left(\frac{\mathrm dy}{\mathrm dt}\right)^2} \,\mathrm dt$

In this case, we have

x(t) = exp(t ) + exp(-t ) ==> dx/dt = exp(t ) - exp(-t )

y(t) = 5 - 2t ==> dy/dt = -2

and [a, b] = [0, 2]. The length of the curve is then

$\displaystyle\int_0^2 \sqrt{\left(e^t-e^{-t}\right)^2+(-2)^2} \,\mathrm dt = \int_0^2 \sqrt{e^{2t}-2+e^{-2t}+4}\,\mathrm dt$

$=\displaystyle\int_0^2 \sqrt{e^{2t}+2+e^{-2t}} \,\mathrm dt$

$=\displaystyle\int_0^2\sqrt{\left(e^t+e^{-t}\right)^2} \,\mathrm dt$

$=\displaystyle\int_0^2\left(e^t+e^{-t}\right)\,\mathrm dt$

$=\left(e^t-e^{-t}\right)\bigg|_0^2 = \left(e^2-e^{-2}\right)-\left(e^0-e^{-0}\right) = \boxed{e^2-\frac1{e^2}}$

5 0

2 years ago

What is the solution of 3/x+8 =-4? Ox= -72 O x= -66 O x = 58 O no solution

castortr0y [4]

Answer:

There is no solution the answers there is not the right answer

4 0

2 years ago

I don’t understand it .

alexira [117]

Answer:

Step-by-step explanation:

8 0

2 years ago

How do I solve that equation

rewona [7]

Solving: (5)(3 - 1) + 4

Step One: Subtract 1 from 3 which is 2
5(3 − 1) + 4

Step Two, Multiply 5 by 2 which is 10=(5)(2) + 4

Step Three, Add 4 to 10 which is 14=10+4

=14

Answer:
(A)14

Hope this helps!

3 0

2 years ago

Read 2 more answers