1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Andru [333]
3 years ago
11

The product of two consecutive numbers is 4 more than three times the larger. find the integer​

Mathematics
1 answer:
Stella [2.4K]3 years ago
7 0

Answer:

Step-by-step explanation:

Let the first integer be x, then the next is x+1.

x(x + 1) = 3(x + 1) + 4

x^2 + x = 3x+ 3 + 4

x^2 + x - 3x - 7 = 0

x^2 - 2x - 7 = 0

Solving this does not give an integer so maybe there's something wrong with the question??

You might be interested in
TJ rented a truck to move to a new apartment. The regular price of a truck rental is $200. TJ has a 15% off coupon, He wants to
Elina [12.6K]

Answer: $170

Step-by-step explanation:

15% of 200 is equal to $30.

200 - 30 = 170

The answer to the question is 170.

8 0
3 years ago
Read 2 more answers
For a data set with a mean of 150 and a standard Deviation of 15, use chebyshev theorem to find the interval of which 75% of the
svp [43]
The Chebychev's theorem states that for any numerical data set,
1.) at least \frac{3}{4} of the data lie within two standard deviations of the mean;
2.) <span> at least </span><span><span>\frac{8}{9} of the data lie within three standard deviations of the mean</span>;
3.) at least </span><span><span>1-\frac{1}{k^2} of the data lie within k standard deviations of the mean,</span> where k is any positive whole number that is greater than 1.</span>

Thus, given a data set with a mean of 150 and a standard Deviation of 15, 75% of the data represent \frac{3}{4} of the data, and according to Chebychev's theorem, <span>at least \frac{3}{4} of the data lie within two standard deviations of the mean.

Thus, 75% of the data will fall within the interval
150\pm2(15)=150\pm30=(150-30,\ 150+30)=(120,\ 180).

Therefore, 75% of the data will fall within the interval 120 to 180.</span>
7 0
3 years ago
Which number is closest to the median of the data set represented by the box-and-whisker plot below?
gregori [183]

Answer:

84

Step-by-step explanation:

6 0
2 years ago
In the diagram below, triangle A’B‘C‘ is a transformation of triangle ABC, and Triangle A”B”C” is a transformation of Triangle A
jeka57 [31]

Answer:

B. i think?

Step-by-step explanation:

5 0
4 years ago
This is the set made taking all the elements from two sets, not repeating any elements
Nadya [2.5K]
Union of sets is the that is made taking all the elements from two sets, not repeating any elements. It is denoted by U. <span>It is one of the fundamental operations through which </span>sets<span> can be combined and related to each other. Hope this answers the question.</span>
3 0
3 years ago
Other questions:
  • Given the equation Y -3 equals 1/2 (X +6 )in point slope form identify the equation of the same line in standard form
    12·1 answer
  • HELPPPPPPPP!!! The figure is a cone with a sphere within it.
    15·1 answer
  • If f(a)=b and g(b)=c are functions then domain and range of fog and gof equals to​
    9·1 answer
  • I need help with number 17 ASAP
    9·1 answer
  • Find the length of the missing side for each polygon so it has a perimeter given perimeter equals 35 cm
    10·1 answer
  • The graph of y = h (x) is a line segment joining the points (-7,-5) and (-1,-2) drag the endpoints of the segment below to graph
    12·1 answer
  • Solve for x. Round your answer to the nearest hundredth.<br><br> 16^x-7=19
    12·1 answer
  • A car has 2gallons of gas. The car gets 30miles/gallon. Enter the conversion factor
    14·2 answers
  • Question 17 Multiple Choice Worth 1 points) (06.02 LC) Which of these is the algebraic expression for "5 times the sum of 2 and
    6·1 answer
  • Solve for x. <br> A. 19.25<br> B. 14<br> C. 10<br> D. 6.5
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!