Use the following data set (6, 4, 4, 5, 1, 8, 10, 7, 8, 6, 6, 7, 5, 4, 6) What kind of data point is the value 1?

Can Someone Please Help ASAP! F(x) = -2 (-3+3) +1

lisov135 [29]

Answer: Your question is written f(x) = -2*(-3+3)+1. I'll assume you need the answer for just the one value of x (-3)? If so, f(-3) = 1.

Step-by-step explanation:

f(x) = -2*(-3+3)+1

f(x) = -2*(0)+1

f(x) = 1

Other values x for the equation f(x) = -2*(x+3)+1:

-2 is -1

1 is -7

3 is -11

3 0

2 years ago

Please help!! Pleaseeee

blsea [12.9K]

Answer:

pretty sure its the first and 3rd one sorry if im wrong

Step-by-step explanation:

6 0

2 years ago

Please Answer I will make you brainiest Could you please also explain I don't get it :(

aivan3 [116]

Answer:

C, 2.15

Step-by-step explanation:

Arabian Plate: 1.29x10^-4 = .000129

African Plate: 6x10^-5 = .000006

Once you've converted both into standard form, divide them to find the difference.

.000129/.000006 = 2.15

3 0

3 years ago

Hypothesis Testing

Yuri [45]

Answer:

Problem 1: We conclude that less than or equal to 50% of adult Americans without a high school diploma are worried about having enough saved for retirement.

Problem 2: We conclude that the volume of Google stock has changed.

Step-by-step explanation:

Problem 1:

We are given that in a recent survey conducted by Pew Research, it was found that 156 of 295 adult Americans without a high school diploma were worried about having enough saved for retirement.

Let p = proportion of adult Americans without a high school diploma who are worried about having enough saved for retirement

So, Null Hypothesis, $H_0$ : p $\leq$ 50% {means that less than or equal to 50% of adult Americans without a high school diploma are worried about having enough saved for retirement}

Alternate Hypothesis, $H_A$ : p > 50% {means that a majority of adult Americans without a high school diploma are worried about having enough saved for retirement}

This is a right-tailed test.

The test statistics that would be used here is One-sample z-test for proportions;

T.S. = $\frac{\hat p-p}{\sqrt{\frac{p(1-p)}{n} } }$ ~ N(0,1)

where, $\hat p$ = sample proportion of adult Americans who were worried about having enough saved for retirement = $\frac{156}{295}$ = 0.53

n = sample of adult Americans = 295

So, the test statistics = $\frac{0.53-0.50}{\sqrt{\frac{0.50(1-0.50)}{295} } }$

= 1.03

The value of z-test statistics is 1.03.

Also, the P-value of the test statistics is given by;

P-value = P(Z > 1.03) = 1 - P(Z $\leq$ 1.03)

= 1 - 0.8485 = 0.1515

Now, at a 0.05 level of significance, the z table gives a critical value of 1.645 for the right-tailed test.

Since the value of our test statistics is less than the critical value of z as 1.03 < 1.645, so we insufficient evidence to reject our null hypothesis as it will not fall in the rejection region.

Therefore, we conclude that less than or equal to 50% of adult Americans without a high school diploma are worried about having enough saved for retirement.

Problem 2:

We are given that a random sample of 35 trading days in 2014 resulted in a sample mean of 3.28 million shares with a standard deviation of 1.68 million shares.

Let $\mu$ = mean daily volume in Google stock

So, Null Hypothesis, $H_0$ : $\mu$ = 5.44 million shares {means that the volume of Google stock has not changed}

Alternate Hypothesis, $H_A$ : $\mu$ $\neq$ 5.44 million shares {means that the volume of Google stock has changed}

This is a two-tailed test.

The test statistics that would be used here is One-sample t-test statistics because we don't know about the population standard deviation;

T.S. = $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ ~ $t_n_-_1$

where, $\bar X$ = sample mean volume in Google stock = 3.28 million shares

s = sample standard deviation = 1.68 million shares

n = sample of trading days = 35

So, the test statistics = $\frac{3.28-5.44}{\frac{1.68}{\sqrt{35} } }$ ~ $t_3_4$

= -7.606

The value of t-test statistics is -7.606.

Also, the P-value of the test statistics is given by;

P-value = P( $t_3_4$ < -7.606) = Less than 0.05%

Now, at a 0.05 level of significance, the t table gives a critical value of -2.032 and 2.032 at 34 degrees of freedom for the two-tailed test.

Since the value of our test statistics doesn't lie within the range of critical values of t, so we sufficient evidence to reject our null hypothesis as it will fall in the rejection region.

Therefore, we conclude that the volume of Google stock has changed.

8 0

2 years ago

My question is in the picture, pls help

Brums [2.3K]

Answer: I'm pretty sure its term but i'm sorry if its not.

Step-by-step explanation:

4 0

2 years ago