Use the following data set (6, 4, 4, 5, 1, 8, 10, 7, 8, 6, 6, 7, 5, 4, 6) What kind of data point is the value 1?

Help!! 30 points!!

erica [24]

Answer:

a. 47.6mph (distance divided by time = speed. divide each rowers distance by their speed, then add them all)

b. 1.26 minutes per mile (i used a calculator so i dunno how to explain)

let me know if this is right or not :)

6 0

3 years ago

HELP ASAP!!!! During a promotional weekend, a state fair gives a free admission to every 158th person that enters the fair. On S

Alex73 [517]

243 because if you divide and subtract it would culminate to the amount of people

5 0

3 years ago

Can anyone help me with this one question??

AnnyKZ [126]

The correct answer is 14yds

7 0

3 years ago

HELP ILL AWARD BRAINLIEST

inna [77]

Answer:

Think about it

Step-by-step explanation:

If you made $20 in 2 hrs you made $10 per hour

To find out how much you make per certain number of hrs multiply $10 by the number of hours

The equation is y = 10x + 0 <-- this is also answer to number 4

10x is the constant of proportionality I think.

5 0

4 years ago

Read 2 more answers

Suppose 52% of the population has a college degree. If a random sample of size 563563 is selected, what is the probability that

amm1812

Answer:

The value is $P(| \^ p - p| < 0.05 ) = 0.9822$

Step-by-step explanation:

From the question we are told that

The population proportion is $p = 0.52$

The sample size is n = 563

Generally the population mean of the sampling distribution is mathematically represented as

$\mu_{x} = p = 0.52$

Generally the standard deviation of the sampling distribution is mathematically evaluated as

$\sigma = \sqrt{\frac{ p(1- p)}{n} }$

=> $\sigma = \sqrt{\frac{ 0.52 (1- 0.52 )}{563} }$

=> $\sigma = 0.02106$

Generally the probability that the proportion of persons with a college degree will differ from the population proportion by less than 5% is mathematically represented as

$P(| \^ p - p| < 0.05 ) = P( - (0.05 - 0.52 ) < \^ p < (0.05 + 0.52 ))$

Here $\^ p$ is the sample proportion of persons with a college degree.

So

$P( - (0.05 - 0.52 ) < \^ p < (0.05 + 0.52 )) = P(\frac{[[0.05 -0.52]]- 0.52}{0.02106} < \frac{[\^p - p] - p}{\sigma } < \frac{[[0.05 -0.52]] + 0.52}{0.02106} )$